13,75 % NaCl
The percent concentration is 13,75 %.
Haemocyanins are a group of proteins.
Check the spelling: 150 M ?
First.Get moles sodium sulfate.5.35 grams Na2SO4 (1 mole Na2SO4/142.05 grams)= 0.0377 moles Na2SO4-------------------------------------Second.Molarity = moles of solute/Liters of solution ( 330 mL = 0.33 Liters )Molarity = 0.0377 moles Na2SO4/0.33 Liters= 0.114 M Na2SO4=============
The percentage of solute in the solution is calculated by dividing the mass of the solute recovered (14.3g) by the initial mass of the solution (125g) and then multiplying by 100. Percentage of solute = (14.3g / 125g) * 100 = 11.44%, or approximately 11.4%.
The percent concentration is 13,75 %.
32.4
That depends on how much solvent you are dissolving the 9 grams of salt in.
The percentage concentration of the solution can be calculated as (mass of solute / total mass of solution) x 100. In this case, the mass of the solute (AgNO3) is 5.48 grams and the total mass of the solution is 5.48 grams (AgNO3) + 25.0 grams (water) = 30.48 grams. Therefore, the percentage concentration is (5.48 / 30.48) x 100 ≈ 17.98%.
Haemocyanins are a group of proteins.
The molarity of the solution is 0.5 M.
This is (mass of solute) divided by (mass of total solution) expressed as a percentage. The solute is what you are dissolving into the solution. Example: you have 90 grams of water, and you add 10 grams of salt (sodium chloride). The water is the solvent, sodium chloride is the solute, and the solution is salt water. 90 grams + 10 grams = 100 grams (mass of total solution). (10 grams) / (100 grams) = 0.1 --> 10% mass mass percent concentration.
grams solute ------------------ x 100 grams solution
200 grams of solution will contain 200 x 4% or 200 x 0.04 = 8.0 total grams of solute.
Check the spelling: 150 M ?
First.Get moles sodium sulfate.5.35 grams Na2SO4 (1 mole Na2SO4/142.05 grams)= 0.0377 moles Na2SO4-------------------------------------Second.Molarity = moles of solute/Liters of solution ( 330 mL = 0.33 Liters )Molarity = 0.0377 moles Na2SO4/0.33 Liters= 0.114 M Na2SO4=============
To find the dissolving rate, you divide the time by the mass. --> 200s/5grams=40mL/s