If you are rounding a 4 digit number to 3 significant figures, then you're rounding to the nearest ten. The 4th digit is 7, so since this digit is >= 5, you should round up the 3rd digit. 1467 becomes 1470. In scientific notation you would express this as 1.47 x 103 to make it clear that there are only 3 significant figures.
Three. The two zeros on the end are just placeholders. 30900 has 3 significant figures.
That depends on the context in which it is found, or the calculation(s) involved. It should have no more significant figures than the value with the least number of sig. figs.
The value 24.503 has 5 significant figures.
The LEFT zeros are place holders, which are not contibuting to significance.0.0360 = 3.60 X 10-2So, actually, there are 3 significant digits. The '3' and '6' and the '0'; this one -AFTER the 6- is not a place holderbut an indicator of the precision of the number - a significant digit.0.036 has 2 significants, and 0.0360 has 3 significant numbers.
There are two significant figures in 0.045.
1470
9,682 rounded to three significant figures is 9,680.
1,782,739 rounded to four significant figures is 1,783,000.
When the value 4,449 is rounded to two significant figures the number should be reported as 4,400
1050 contains 4 significant digits and cannot be rounded to two significant figures without changing the value of the number.
Because, to two significant figures, the value of 2,974894956..... is rounded off to 3,0The question was posed with three significant figures so you could argue that the answer should be 2,97.
Three
2 significant figures.
1.414 to three significant figures.
3 of them.
Three. The two zeros on the end are just placeholders. 30900 has 3 significant figures.
The rounded value is 10. See also the links below. * * * * * However, there is no such thing as the correct number of significant figures (sf). SF depends on the context as well as the SF of the numbers used to compute the value.