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10 mm = 1 cm, therefore, a cylinder 380 mm x 930 mm = 38 cm x 98 cm. The volume of a cylinder is calculated by Pi x r2 x d, where Pi ~ 3.14, r = radius of the cylinder = 38 cm/2 and d = the cylinder height = 93 cm. 3.14 x (38/2)2 x 93 = 105,419 cm3 or 105,419 cc or cubic centimeters 1 cc = 1 ml, 1,000 ml = 1 liter, 3.785 liters ~ 1 gallon 105,419 ml = 105.419 liters = 27.9 gallons of water at 60oF.

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1mo ago

To find the volume of a cylinder, you can use the formula V = πr^2h, where r is the radius and h is the height. In this case, since the dimensions are given in millimeters, convert them to the same unit. The radius would be half the diameter, so the radius is 190mm and the height is 930mm. Plug these values into the formula to find the volume in cubic millimeters.

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Q: What is the volume of water in a cylinder 380millimeters by 930millimeters?
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What is the volume of a metal cylinder weighing 18.03 grams if you put it in 15mL of water and it rises to 21.4 mL?

The increase in volume of the water when the cylinder is added is equal to the volume of the cylinder. So, the volume of the cylinder is 21.4 mL - 15 mL = 6.4 mL. Since the metal cylinder is immersed in water, the volume of the metal cylinder is 6.4 mL.


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Related questions

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To determine the volume of an irregular object using graduated cylinders, you fill a graduated cylinder with water right to the top, then submerge the object in the water. Measure the water that overflows using a second graduated cylinder, and read the water level in it in cc's or cubic inches. That is the object's volume.


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To find the volume of an irregular shape, you need to use the water displacement method. If the object can fit into a graduated cylinder, fill the cylinder with enough water to adequately cover the object, but don't put the object inside the cylinder yet. Record the amount of water in the cylinder. Carefully drop the object into the cylinder. This will cause a rise in the water in the cylinder. Record this second volume. Subtract the first volume from the second volume, and the difference is the volume of the irregular object. For larger objects, use an overflow can.


How could the volume of a 12 sided object be found using water and a graduated cylinder?

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