Jobs that use diameter are ones that uses diameter
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∙ 12y agoJobs that involve engineering, manufacturing, construction, and design often use diameter as a measurement. These could include mechanical engineers, machinists, architects, and carpenters, among others. Other industries that may use diameter include automotive, aerospace, and medical devices.
To reduce tubing diameter, you can use a tube expander tool to compress the tubing or a tube cutter to trim the edges. Alternatively, you can insert a smaller diameter tube into the existing tubing or use a reducing fitting designed for this purpose.
millimetres or mm
Vernier calipers can be used to accurately measure a hard rod's diameter within seconds. And it's very easy to use.
Geologists use the scale known as the Wentworth scale to measure the size of loose rocks based on their diameter. The scale categorizes particles into different size ranges, such as gravel, sand, silt, and clay, based on their diameter in millimeters.
No, a 0.008 inch diameter fishing line is not equal to a 15 mm diameter fishing line. To convert inches to millimeters, you can use the conversion factor 1 inch = 25.4 mm. Therefore, 0.008 inch is equal to approximately 0.2032 mm.
They work with rods and they have to measure the diameter of tables sometime. If they're making round furniture of any type, of course they will use it.
diameter of a circle times pi is the circumference, the perimeter of a circle.
Lots of jobs use landforms
There are no jobs that don't use numbers?
When dealing with pipe the volume is more important, therefore, I would use the inside diameter.
divide the diameter by 2! doy!
you double the radius to find the diameter.
In a circle, the radius is half of the diameter.
Bob tried to find the diameter of the circle.
jobs
To find area of a circle using diameter, you use this formuler. Area=pi(diameter/2)(diameter/2)
If you are given the radius of the circle, you can use the formula: diameter = 2*radius If you are given the circumference of the circle, you can use the formula: diameter = circumference/pi