For a motor drawing 6 amps, a minimum wire size of 18 AWG (American Wire Gauge) is typically sufficient for short runs. However, for longer distances or to ensure safety and reduce voltage drop, it's advisable to use 16 AWG wire. Always consult local electrical codes and regulations to ensure compliance with safety standards in your area.
For a fan motor with a current draw of 6 amps, a 14-gauge wire is typically sufficient for most indoor applications. However, it's essential to consider the length of the wire run and any local electrical codes that may apply. If the wire run is particularly long (over 50 feet), you might want to consider using a 12-gauge wire to minimize voltage drop. Always consult with a licensed electrician for specific requirements and safety guidelines.
To calculate the amps drawn by an 18kW motor, you can use the formula: Amps = Power (Watts) / Voltage (Volts). Assuming a standard voltage of 120V, the motor would draw approximately 150Amps. Note that actual amps will depend on the specific voltage of the motor.
A pool pump motor which is drawing half the amps listed on its nameplate can indicate a problem with the windings or a lack of incoming current. Pumps will only draw as many amps as are required to operate under the current load.
Presuming single phase and 1500 rpm. Normal running current would nearly 10 Amps but varies considerably. A real cheap one running at 3000/3600 rpm could exceed 12 amps. At 240 volt, all should be run off 15 Amp line.
To calculate the amperage needed for a 30 horsepower motor at 240 volts, you can use the formula: Amps = (Horsepower × 746) / Voltage. For a 30 HP motor, this would be (30 × 746) / 240, which equals approximately 93.15 amps. Therefore, you would need around 93 amps for a 30 HP motor operating at 240 volts.
Need to know what the voltage of the motor is.
For a fan motor with a current draw of 6 amps, a 14-gauge wire is typically sufficient for most indoor applications. However, it's essential to consider the length of the wire run and any local electrical codes that may apply. If the wire run is particularly long (over 50 feet), you might want to consider using a 12-gauge wire to minimize voltage drop. Always consult with a licensed electrician for specific requirements and safety guidelines.
To calculate the amps drawn by an 18kW motor, you can use the formula: Amps = Power (Watts) / Voltage (Volts). Assuming a standard voltage of 120V, the motor would draw approximately 150Amps. Note that actual amps will depend on the specific voltage of the motor.
Watts = Volts times Amps. Therefore, if the voltage was 220 volts, the motor would draw 500 amps. If the voltage was 4,000 volts, the motor would draw 27.5 amps. The voltages for large powerful motors tend to be relatively high, for example in the 380 Volts to 11,500 Volts range.
FLA is the nameplate amperage rating of the motor when it is running at its designed horsepower and on the motors designed voltage. 746 watts = 1 HP. The FLA of a 1 HP motor at 240 volts would be W = amps x volts, Amps = Watts/Voltage. 746/240 = 3.1 amps full load. Overload the motor and the amps go higher, motor running at no load amps are lower than FLA
A pool pump motor which is drawing half the amps listed on its nameplate can indicate a problem with the windings or a lack of incoming current. Pumps will only draw as many amps as are required to operate under the current load.
T430.247 of the NEC shows that a 1 hp motor operating at full load on 115v will draw 16 amps, called Full Load Current (FLC). Conductors supplying this motor are required to be 125% of FLC which is 20 amps. Motor circuits are complicated things and do not follow the rules of other circuits. This motor, while drawing a maximum of 16 amps at full load and supplied with #12 AWG copper conductors can be protected by a breaker of 40 amps.
Presuming single phase and 1500 rpm. Normal running current would nearly 10 Amps but varies considerably. A real cheap one running at 3000/3600 rpm could exceed 12 amps. At 240 volt, all should be run off 15 Amp line.
To calculate the amperage needed for a 30 horsepower motor at 240 volts, you can use the formula: Amps = (Horsepower × 746) / Voltage. For a 30 HP motor, this would be (30 × 746) / 240, which equals approximately 93.15 amps. Therefore, you would need around 93 amps for a 30 HP motor operating at 240 volts.
Full load amps is the maximum rated amps that the motor should draw according to its nameplate rating. Running load amps is the actual amperage the motor is drawing at that point in time when the test is taken. Some motor loads vary depending on if the load is cyclic. The reading on this type of motor would be from no load amps to full load amps.
"Locked Rotor Current" also called LRA which stands for Locked Rotor Amps, is commonly found on electric motor nameplates. Locked Rotor essentially means the motor is not turning. The current or amps in this case have to do with the amount of electrical energy required to start the motor. At the instant the motor is switched on, it is not turning, and draws the maximum current. As the motor starts to turn, the current goes down. This required energy is much greater than the Full Load Amps or Running Amps, which is the current drawn when the motor is running at normal speed under full load. The current required to start the motor will depend on the type of motor as well as the specified design voltage required for the motor, typically the higher the voltage, the lower the required amperage or current. The term also applies to equipment such as Air Conditioners which have an enclosed motor inside the compressor, as well as the condenser fan(s) etc. Depending on the type of motor, LR current can be anywhere from 3 to 8 times the normal running current, also called RLA, or running load amps.
Measure the current on the incoming side of the starter.