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An empty vial has a mass of 96.94 g If the vial has a mass of 204.69 g when completely filled with liquid mercury d 13.53 gcm3 what is the volume of the vial?
To find the volume of the vial, we first need to calculate the mass of the liquid mercury. Mass of liquid mercury = 204.69 g - 96.94 g = 107.75 g Now, we can use the density of mercury (13.53 g/cm^3) to find the volume: Volume = Mass / Density = 107.75 g / 13.53 g/cm^3 ≈ 7.97 cm^3.
The mass of 100 ml of mercury is 1350 g In this case what is the calculated density of mercury?
Density is calculated as mass divided by volume. In this case, the mass is 1350 g and the volume is 100 ml. Converting 100 ml to cubic centimeters (1 ml = 1 cm^3), the density of mercury is 13.5 g/cm^3.
What is the density of mercury if a 25.0 mL sample has a mass of 338.35 g?
The density of mercury is found by dividing its mass by volume. In this case, the density is 13.53 g/mL.
What volume is occupied by 8.00 grams of helium gas?
4 g of helium occupies 22.414 liters So, 0.8 g will occupy 4.483 liters
Mercury has a specific gravity of 13.6. How many mm of mercury have a mass of 0.35?
To calculate the volume of mercury with a mass of 0.35 g, you need to use the formula: volume = mass / specific gravity. So, the volume of mercury = 0.35 g / 13.6 g/cm^3 = 0.0257 cm^3. Since 1 mm^3 = 1 μL, the volume is 0.0257 cm^3 = 25.7 μL.
