A 1.0000 g sample of water will occupy 1.0000 ml in volume, as water has a density of 1 g/ml at 24°C. Water's density is close to 1 g/ml across a wide range of temperatures.
lead and water will occupy the same volume. however the Density of lead is 207.2 g/L (grams per liter) and the Density of H2O is only 18.02 g/L so if you had the same volume of lead and water the lead would be heavier. But if you had the same Weight of both water and lead the water would have a larger volume.
The volume of ammonia is 19,5 L.
The volume of carbon tetrachloride can be calculated using the formula: Volume = Mass / Density. So, the volume of 35.2 g of carbon tetrachloride with a density of 1.00 g/ml would be 35.2 ml.
The density of mercury (Hg) is 13.6 g/mL. Therefore, the mass of Hg that will occupy a volume of 50.0 mL can be calculated using the formula: mass = volume x density. Substituting the values, we get mass = 50.0 mL x 13.6 g/mL = 680 grams.
A 1.0000 g sample of water will occupy 1.0000 ml in volume, as water has a density of 1 g/ml at 24°C. Water's density is close to 1 g/ml across a wide range of temperatures.
lead and water will occupy the same volume. however the Density of lead is 207.2 g/L (grams per liter) and the Density of H2O is only 18.02 g/L so if you had the same volume of lead and water the lead would be heavier. But if you had the same Weight of both water and lead the water would have a larger volume.
Since the density (mass divided by volume) of water is about 1.0 g/mL the volume of 6.5 gram is6.5(g) / 1.0(g/mL) = 6.5 mL
The 1000 grammes of ethanol will occupy a greater volume because its specific gravity is lower than that of water. s.g. water = ~1.0 s.g. ethanol = ~ 0.794
The volume of ammonia is 19,5 L.
0.00922 g of H2 gas will occupy approximately 0.100 L at STP
100g of lead would occupy a larger volume compared to 100g of water because lead has a higher density of 11.34 g/ml, whereas water has a density of 0.995 g/ml. The higher the density of a substance, the more mass it can hold in a smaller volume.
It is not possible to answer the question since that depends on the density of the item. Consider 22 g of water and 22 g of lead. The lead will occupy much less volume because it has a much greater density.
To find the volume of 15.7 g of calcium chloride with a density of 2.50 g/cm³, you would use the formula: Volume = Mass / Density. Plug in the values: Volume = 15.7 g / 2.50 g/cm³ = 6.28 cm³. Therefore, 15.7 g of calcium chloride would occupy a volume of 6.28 cm³.
The volume 396g would occupy depends on the density of the substance. To calculate the volume, you need to know the density of the material. By dividing the mass (396g) by the material's density (in g/cm^3 or g/mL), you can determine the volume occupied by 396g of that substance.
The density of calcium chloride is approximately 2.15 g/cm3. By dividing the mass by the density, you can calculate the volume. In this case, 15.7 g of calcium chloride would occupy around 7.3 cm3 of volume.
6.28cm3