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Name the two physical quantities which can be obtained from the velocity-time graph?
well, the area under the curve between a time interval is equal to the distance traveled on that specific time interval. So one quantity is distance. As for another quantity, the answer would be velocity, but I think they may want a less obvious answer. A quantity out side of velocity could be instantaneous acceleration. This is given by the slope of the the tangent line to the velocity-time graph. Hope this helps you answer your question. Though I think the most simple way to understanding why is to take a course of calculus.
Name 2 physical quantities that can be obtained from v-t graph?
well, the area under the curve between a time interval is equal to the distance traveled on that specific time interval. So one quantity is distance. As for another quantity, the answer would be velocity, but I think they may want a less obvious answer. A quantity out side of velocity could be instantaneous acceleration. This is given by the slope of the the tangent line to the velocity-time graph.Hope this helps you answer your question. Though I think the most simple way to understanding why is to take a course of calculus.
How do you figure out the starting point of a distance vs time graph when given the velocity vs time graph and a function?
To find the starting point of a distance vs time graph from a velocity vs time graph and a function, you would integrate the velocity function to find the displacement function. The starting point of the distance vs time graph corresponds to the initial displacement obtained from the displaced function.
Area under the velocity time graph line is 40 M. What physical quantity does this area represent?
It represent the distance covered is 40 metre.
How do you make an acceleration time graph from the data of a velocity time graph?
To create an acceleration-time graph from a velocity-time graph, you need to find the slope of the velocity-time graph at each point. The slope represents the acceleration at that specific instant. Plot these acceleration values against time to get the acceleration-time graph.
Name the two physical quantities which can be obtained from the velocity-time graph?
well, the area under the curve between a time interval is equal to the distance traveled on that specific time interval. So one quantity is distance. As for another quantity, the answer would be velocity, but I think they may want a less obvious answer. A quantity out side of velocity could be instantaneous acceleration. This is given by the slope of the the tangent line to the velocity-time graph. Hope this helps you answer your question. Though I think the most simple way to understanding why is to take a course of calculus.
How is acceleration obtained from a velocity line graph?
Acceleration can be obtained from a velocity line graph by calculating the slope of the line at a particular point. The slope of the line represents the rate of change of velocity, which is the acceleration. The steeper the slope, the greater the acceleration.
Which physical quantity is given by slope of v-t graph?
The physical quantity given by the slope of a velocity-time graph is acceleration. This is because the slope represents the rate of change of velocity over time, which is how acceleration is defined (acceleration = change in velocity / time taken).
What is the unit of a physical quantity which is represented by area under a velocity time graph?
the physical quantity is distance and unit is meters
How can the graph of f(x) 7 be obtained from the graph of y?
It cannot, in any sensible way.
What does displacement divided by time give you?
The Average Velocity on a position time graph or a velocity time graph.
Name 2 physical quantities that can be obtained from v-t graph?
well, the area under the curve between a time interval is equal to the distance traveled on that specific time interval. So one quantity is distance. As for another quantity, the answer would be velocity, but I think they may want a less obvious answer. A quantity out side of velocity could be instantaneous acceleration. This is given by the slope of the the tangent line to the velocity-time graph.Hope this helps you answer your question. Though I think the most simple way to understanding why is to take a course of calculus.
What is the quantity which is measured by the area occupied below the velocity - time graph?
Distance travelled (displacement). Distance = velocity/time, so velocity * time = distance. Likewise, x = dv/dt so the integral of velocity with respect to time (area under the graph) is x, the distance travelled.
Velocity is represented graphically by an what?
By an arrow, a vector. Velocity is a vector quantity that must have both magnitude (speed) and direction (bearing).
How do you figure out the starting point of a distance vs time graph when given the velocity vs time graph and a function?
To find the starting point of a distance vs time graph from a velocity vs time graph and a function, you would integrate the velocity function to find the displacement function. The starting point of the distance vs time graph corresponds to the initial displacement obtained from the displaced function.
What is indicated by a velocity time graph that crosses the x axis?
That the object whose velocity is being graphed has reversed direction (and is now going in the opposite direction). Velocity is a vector quantity: it has both magnitude and direction.
Area under the velocity time graph line is 40 M. What physical quantity does this area represent?
It represent the distance covered is 40 metre.
