784
2 x 2 x 7 x 11 or 2^2 x 7^1 x 11^1
f(x) = 2x + 1 g(x) = x^2 - 7 So f*g(x) = f(g(x)) = f(x^2 - 7) = 2*(x^2 - 7) + 1 = 2*x^2 - 14 + 1 = 2*x^2 - 13
1 x 14, 2 x 7, 7 x 2, 14 x 1
10 + 2(x - 1) + 7 x 3x + 1 =10 + 2x - 2 + (7 x 3x) + 1 =10 + 2x - 2 + 21x + 1 =2x + 21x + 10 - 2 + 1 =23x + 9
2744 = 1 x 1 x 2 x 2 x 2 x 7 x 7 x 7 Make 3 groups of these factors and multiply the numbers in each group to get 3 numbers, eg: {1}, {1}, {2, 2, 2, 7, 7, 7} = 1 x 1 x 2744 {1}, {1, 2}, {2, 2, 7, 7, 7} = 1 x 2 x 1372 {1, 2}, {1, 2, 7}, {2, 7, 7} = 2 x 14 x 98 {1, 2, 7}, {1, 2, 7}, {2, 7} = 14 x 14 x 14 There are many more such answers.
784
70 = 7 x 10 = 7 x 2 x 5 56 = 7 x 8 = 7 x 2 x 2 x 2 Common factors are 1, 2, 7 and 14
2 x 2 x 7 x 11 or 2^2 x 7^1 x 11^1
f(x) = 2x + 1 g(x) = x^2 - 7 So f*g(x) = f(g(x)) = f(x^2 - 7) = 2*(x^2 - 7) + 1 = 2*x^2 - 14 + 1 = 2*x^2 - 13
Factors of 98 are 1, 2, 7, 14, 49, and 98.
Factor them. 2 x 2 1 x 7 2 x 2 x 3 3 x 7 The answer is 1 x 2 x 2 x 3 x 7 or 84
The power is 1. 2 x 7 x 11 = 21 x 71 x 111 or (2 x 7 x 11)1
1 x 98, 2 x 49, 7 x 14, 14 x 7, 49 x 2, 98 x 1 = 98
1 x 14, 2 x 7, 7 x 2, 14 x 1
There are an infinite number of possibilities. Even if you only use whole numbers, you still have a few choices: 1 x 28 1 x 2 x 14 1 x 4 x 7 2 x 2 x 7 1 x 2 x 2 x 7 2 x 14 4 x 7
2 x 2 x 7 1 x 1 x 28 1 x 4 x 7