0
This does readily factor!!!
So by trial and error.
Discount '0' because the you are left with '-7'
Try '-1
(-1)^(3) - 5(-1)^(2) - 13(-1) - 7 =>
-1 - 5 + 13 - 7 adding = '0'
Hence x = -1
Therefore ( x + 1) is a factor.
(x+1)
( x^(3) - 5(x^(2) - 13x - 7 = (x^(2)
-x^(3) -x^(2) =
-6x^(2) - 13x = ( x^(2) -6x
6x^(2) + 6x =
-7(x + 1) ( x^(2) - 6x + 7)
(x + 1)(x^(2) - 6x + 7) is fully factored.
If you factor the Quadratic, you will move into the region of IMGINARY (i) numbers.
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