7x + 5y 7(3) + 5(2) 21 + 10 = 31
4x + 5y = 2 and 7x - 2y = 1 From the first equation, x = (2 - 5y)/4 putting this value of x to the second equation, 7(2 - 5y)/4 - 2y =1 => (14 - 35y)/4 - 2y = 1 =>14 - 35y - 8y = 4 =>14 - 43y = 4 =>43y = 10 => y = 10/43 putting y = 10/43 in x = (2 - 5y)/4 => x =( 86 - 50 )/172 => x = 36/172 => x = 9/43 therefore, x = 9/43 and y = 10/43
X = -2(13 + y) / 3x = 5y / 4 - 1
5y + (4 - 2y) = 9 5y + 4 - 2y = 9 3y + 4 = 9 3y = 5 y = 5/3
7x-4=x+2 7x=x+2+4 7x=x+6 7x-x=6 6x=6 X=1
x = 0 and y = 4
7x + 5y 7(3) + 5(2) 21 + 10 = 31
It works out that the solutions are: x = 3 and y = 2
24
It works out that: x = 3 and y = 2
(1, -1)
No, because a slope needs to be negative and opposite the other slope to be perpendicular and in this problem it is not.
8 - 5y = 12 -5y = 4 y = -4/5
If: 4x = 5y Then: x = 5y/4
69
4x + 5y = 2 and 7x - 2y = 1 From the first equation, x = (2 - 5y)/4 putting this value of x to the second equation, 7(2 - 5y)/4 - 2y =1 => (14 - 35y)/4 - 2y = 1 =>14 - 35y - 8y = 4 =>14 - 43y = 4 =>43y = 10 => y = 10/43 putting y = 10/43 in x = (2 - 5y)/4 => x =( 86 - 50 )/172 => x = 36/172 => x = 9/43 therefore, x = 9/43 and y = 10/43
slope intercept form is y = mx + b where m=slope and b=y-interceptfirst solve the equation for y7x-5y=357x=5y+355y=7x-35y=7x/5-35/5y=(7/5)x-7so the slope is 7/5 and the y-intercept is -7