N=19.
If: n squared -n -90 = 0 Then the solutions are: n = 10 or n = -9
abs(9 - n) which is 9 - n if 9 ≥ n and n- 9 if 9 ≤ n
n+4
9% because by definition for any number, n, we have n percent is n/100. For example, 10/100 =10% and 1/100=1% and 200/100=200% and 100/100= 100% By definition you cannot have 200% you can have + 100% .
-19 + 9 = -10n = -19n+9=-10-9 -9n=-19
N=19.
9, 10, 11. Let the middle number be n, then the three numbers are (n-1), n, (n+1) with: (n-1) + n + (n+1) = 30 → 3n = 30 → n = 10 → the numbers are 10-1 = 9, 10 and 10+1 = 11.
6787000 = 6.787 x 10^6, so for N x 10^9 = 6.787 x 10^6, divide both sides by 10^9, and N = 6.787 x 10^-3 = 0.006787
Suppose 9*(n-1) + 9*n + 9*(n+1) = 243 then dividing by n, (n-1) + n + (n+1) = 243/9 = 27 that is, 3n = 27 and so n = 9 So the three numbers are 9*8, 9*9 and 9*10 ie 72, 81 and 90.
Sum of a geometric progression with first term a and constant different r is given by:sum_gp = a(1 - rn)/(1 - r)Required sum is:Sum =0.5 + 0.55 + 0.555 + ... [n terms]= 5 (0.1 + 0.11 + 0.111 + ... [n terms])= 5 (1/10 + 11/100 + 111/1000 + ... [n terms])Multiply by 9/9 (= 1):= 5/9 (9/10 + 99/100 + 999/1000 + ... [n terms])= 5/9 [ (1 - 1/10) + (1 - 1/100) + (1 - 1/1000) + ... + (1 - 1/(10n) ]= 5/9 [ (1 + 1 + 1 + ... [n terms]) - (1/10 + 1/100 + ... + 1/10n) ]= 5/9 [ n - 1/10 (1 - (1/10)n) / (1 - 1/10) ]= 5/9 [ n - 1/9 (1 - (1/10)n) ]= 5/9 [ n - 1/9 (1 - 0.1n) ]= 5/9 [ n - (10n - 1) / (9 x 10n) ]
5/(n - 12) = 10(n + 5) (multiply by the common denominator (n - 120(n + 9) to both sides)[5/(n - 12)][(n - 12)(n + 9)] = [10(n + 5)][(n - 120)(n + 9)] (simplify)5(n + 9) = 10(n - 12)5n + 45 = 10n - 120 (subtract 5n and add 120 to both sides)5n - 5n + 120 + 45 = 10n - 5n + 120 - 120165 = 5n (divide by 5 to both sides)33 = n
To solve the third term of 10-n², substitute the number 3 for n. 10-n² =10-3² =10-9 =1 The third term of 10-n² is 1.
Out 'N' About with R-J- Fritz - 1998 9-10 was released on: USA: 13 May 2006
n + 1/4 = 9/20 n + 5/20 = 9/20 n = 4/20 = 1/5
If: n squared -n -90 = 0 Then the solutions are: n = 10 or n = -9
In general, the number of combinations of n things taken r at a time isnCr = n!/[(n - r)!r!]Thus, we have:10C8= 10!/[(10 - 8)!8!]= 10!/(2!!8!)= (10 x 9 x 8!)/(8! x 2 x 1)= (10 x 9)/2= 5 x 9= 45