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9, 10, 11.

Let the middle number be n, then the three numbers are (n-1), n, (n+1) with:

(n-1) + n + (n+1) = 30

→ 3n = 30

→ n = 10

→ the numbers are 10-1 = 9, 10 and 10+1 = 11.

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9y ago

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9y ago

They are 30/3-1, 30/3 and 30/3+1, that is, 9, 10 and 11.

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Q: What are Three consecutive natural numbers have a sum of 30.?
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