9, 10, 11.
Let the middle number be n, then the three numbers are (n-1), n, (n+1) with:
(n-1) + n + (n+1) = 30
→ 3n = 30
→ n = 10
→ the numbers are 10-1 = 9, 10 and 10+1 = 11.
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It is a statement of numerical fact.
19, 20, 21
The three consecutive even numbers with a sum of 138 are 44, 46 and 48.
5 5 5
Their sum is -12