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9, 10, 11.
Let the middle number be n, then the three numbers are (n-1), n, (n+1) with:
(n-1) + n + (n+1) = 30
→ 3n = 30
→ n = 10
→ the numbers are 10-1 = 9, 10 and 10+1 = 11.
Wiki User
∙ 8y ago
Wiki User
∙ 8y agoThey are 30/3-1, 30/3 and 30/3+1, that is, 9, 10 and 11.
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Type your answer here... Dertermine three consecutive even numbers who's sum is 42?
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