3y+5=y-25 2y=-30 y= -15
Presumably you want to know the value of y. 3y+2y+4+1 = 80 5y+5 = 80 5y = 80-5 5y = 75 y = 15
15 y + 20 = 5(3y + 4)
If you mean: 80 = 3y+2y+4+1 then 80 =5y+5 and so y = 15
If you mean: 3y = 19+5 then the value of y is 8
4y + 4 = 3y - 5 y = -9
5 + 3y = -4 First subtract 5 from both sides. 3y = -9 Then divide both sides by 3. y = -3
-3y + 4 = -1Add 3y to each side:4 = -1 + 3yAdd 1 to each side:5 = 3yDivide each side by 3:y = 5/3
(3y + 5)(y - 2)
x + y = 6 so that -x = y - 6 -x + 3y = -2 that is, y - 6 + 3y = -2 or 4y = 4 or y = 1 and then -x = y - 6 = -5 so that x = 5
3y+5=y-25 2y=-30 y= -15
Presumably you want to know the value of y. 3y+2y+4+1 = 80 5y+5 = 80 5y = 80-5 5y = 75 y = 15
(4, 5)
3y - 3 = 2y + 5 3y - 2y = 5 + 3 y = 8
15 y + 20 = 5(3y + 4)
3y + 4-26 = 0 y = 7.333
If you mean: 80 = 3y+2y+4+1 then 80 =5y+5 and so y = 15