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Presumably you want to know the value of y. 3y+2y+4+1 = 80 5y+5 = 80 5y = 80-5 5y = 75 y = 15

Q: 80 equals 3y plus 2y plus 4 plus 1 is?

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3y + 2y + 4 + 1 = 805y + 5 = 805y = 75y = 15

If you mean: 80 = 3y+2y+4+1 then 80 =5y+5 and so y = 15

The answer to the equation 80 times 3 Y plus 2 Y plus 4 plus 1 equals -15. This is considered to be a math problem.

80+80=160 your welcome

390

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3y+2y+4+1=80 5y+5=80 5y=80-5 5y=75 y=15

3y + 2y + 4 + 1 = 805y + 5 = 805y = 75y = 15

80 = 3y + 2y + 4 + 1 75 = 5y 15 = y y = 15

80 = 3y + 2y + 4 + 1 80 = 5y + 5 80 - 5 = 5y + 5 - 5 75 = 5y 75 / 5 = 5y / 5 15 = y

If you mean: 80 = 3y+2y+4+1 then 80 =5y+5 and so y = 15

The answer to the equation 80 times 3 Y plus 2 Y plus 4 plus 1 equals -15. This is considered to be a math problem.

First, change 2x+6y=32 to x+3y=16. Then solve for x, which is x=-3y+16. Then substitute -3y+16 as x into 5x-2y=12 and solve for y. 5(-3y+16)-2y=12 -15y+80-2y=12 -17y+80=12 -17y=-68 y=4 Then substitute 4 as y in either equation to solve for x. 5x-2(4)=12 5x-8=12 5x=20 x=4 The answer is x=4 and y=4, or (4,4)

4y = 2y + 40 4y - 2y = 2y -2y +40 2y = 40 y = 20 check 4(20) = 2(20) +40 80 = 80

a) 4x+13y=40 b) 4x+3y=-40c) multiply b per(-1)=-4x-3y-40d) sum a and c: 4x+13y-4x-3y=40-(-40)=>10y=80 => y=8to find x replace y per its value in a or b and get x=-16

94+94+80+80=348.

80 80 + —— 160 160 80 + —— 240

80 + 50 = 130