11 Players in a Football Team
11 P in a FT- 11 Players in a Football Team! Answered by Yusuf Ahmed Vaughan sch.
18-ft x 11-ft = 198 square ft
3 ft = 1 yd 34 ÷ 3 = 11 r 1 → 34 = 11×3 + 1 34 ft = (11×3 + 1) ft = 11 × 3 ft + 1 ft = 11 yd 1 ft
how many ft is 11 yds
You need the perimeter but the area of the home is not sufficient to identify its perimeter. All that can be said is that, in the unlikely event that the home is circular, the perimeter will be 142 feet. For any other shape it will be more. And it can be infinitely more. Suppose the home is rectangular, with length = L feet and width = W feet. Then for an area of 1600 sq feet, W must be 1600/L feet Therefore the perimeter, P = 2*(L+W) = 2L + 3200/L feet. If L = 80 ft, then W = 20 ft and P = 200 ft L = 100 ft then W = 16 ft and P = 232 ft L = 160 ft , W = 10 ft and P = 340 ft You can go further: L = 1600 ft, W = 1 ft P = 3202 ft L = 1.6 million ft, W = 0.001 ft and P = 320000.002 ft L = 1.6 billion ft, W = 0.000001 ft and P = 606060.60.. MILES! As you can see, there is no limit!
11 P on a FT = 11 Players on a Football Team.
11 Players on a Football Team.
11 P in a FT- 11 Players in a Football Team! Answered by Yusuf Ahmed Vaughan sch.
It is a letter equation that means "11 Players in a Football Team".
11 Players on a Football Team or Soccer Team
"One Point on a Free Throw" (in basketball).
To find the length when given an area of 33 ft² and a width of 3 ft, you can use the formula for area: Area = Length × Width. Rearranging this gives Length = Area / Width. Thus, Length = 33 ft² / 3 ft = 11 ft. Now, to find the perimeter (P) of a rectangle, use the formula P = 2(Length + Width), which gives P = 2(11 ft + 3 ft) = 28 ft. The area is already given as 33 ft².
18-ft x 11-ft = 198 square ft
3 ft = 1 yd 34 ÷ 3 = 11 r 1 → 34 = 11×3 + 1 34 ft = (11×3 + 1) ft = 11 × 3 ft + 1 ft = 11 yd 1 ft
11 ft. 11+11+6+6=34
11 ft = 3.35 metres
how many ft is 11 yds