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How do you rationalize the denominator in this expression 5 divided by square root of 3 minus 1?
5/(√3 - 1)= 5(√3 + 1)/(√3 - 1)(√3 + 1)= (5√3 + 5)/[(√3)2 - 12)= (5√3 + 5)/(3 - 1)= 5√3 + 5)/2= 5√3/2 + 1/2
What fraction of 2 1 5 is 3 1 5?
2==5 and 5!=3 or (5-2)^2>=1
What are subsets of the set N containing the numbers 1 2 3 4 and 5?
There are 32 possible subset from the set {1, 2, 3, 4, 5}, ranging from 0 elements (the empty set) to 5 elements (the whole set): 0 elements: {} 1 element: {1}, {2}, {3}, {4}, {5} 2 elements: {1, 2}, {1, 3}, {1, 4}, {1, 5}, {2, 3}, {2, 4}, {2, 5}, {3, 4,}, {3, 5}, {4, 5} 3 elements: {1, 2, 3}, {1, 2, 4}, {1, 2, 5}, {1, 3, 4}, {1, 3, 5}, {1, 4, 5}, {2, 3, 4}, {2, 3, 5}, {2, 4, 5}, {3, 4, 5} 4 elements: {1, 2, 3, 4}, {1, 2, 3, 5}, {1, 2, 4, 5}, {1, 3, 4, 5}, {2, 3, 4, 5} 5 elements: {1, 2, 3, 4, 5} The number of sets in each row above is each successive column from row 5 of Pascal's triangle. This can be calculated using the nCr formula where n = 5 and r is the number of elements (r = 0, 1, ..., 5). The total number of subset is given by the sum of row 5 of Pascal's triangle which is given by the formula 2^row, which is this case is 2^5 = 32.
At which place in this series would you find the first seven 1 1 1 1 1 1 2 1 1 1 3 1 2 2 2 2 3 2 2 2?
It is Mathematically impossible. In order to find a single 7 in 1 1 1 1 2 1 1 1 3 1 2 2 2 2 3 2 2 2 The order would be as a requirement: 1 1 1 1 2 1 1 1 1 3 2 2 2 2 3 2 2 2 2 4 3 3 3 3 4 3 3 3 3 5 4 4 4 4 5 4 4 4 4 6 --- --- 5 5 5 5 6 5 5 5 5 7 (THERE!) If in that order the first 7 would be the 50th number. as from that you can see that the first 14 would be the 100th number, as well as the 21 being the 150th and so on.
What is 2 over 5 divided by 1 over 3 as a fraction?
(2/5) / (1/3) = (2/5)*(3/1) = 6/5 = 11/5
