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Q: 1 2x - 1 - 2 3x 2?
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What does x equal in 3x-3x-1plus2x-1?

3x - 3x -1 + 2x -1 = 0 0 - 1 + 2x - 1 = 0 2x - 2 = 0 2x = 2 x = 1


X2 over 3x2 -5x-2 -2x over 3 x plus 1 x 1 over x-2?

x2/(3x2 - 5x - 2) - [2x/ (3x + 1)][1/(x - 2)] = x2/(3x2 - 6x + x - 2) - 2x/(3x + 1)(x - 2) = x2/[3x(x - 2) + (x - 2)] - 2x/(3x + 1)(x - 2) = x2/(3x + 1)(x - 2) - 2x/(3x + 1)(x - 2) = (x2 - 2x)/(3x + 1)(x - 2) = x(x - 2)/(3x + 1)(x - 2) = x/(3x + 1)


How do you factor 2x-3x-2?

As written, that's -x - 2, which is in its simplest form. 2x^2 - 3x - 2 = (2x + 1)(x - 2)


What is the factorization of the trinmomial 12x2-2x-2?

2(3x + 1)(2x - 1)


3x plus 5x equals 2x plus 2?

3x + 5x = 2x + 28x = 2x + 26x = 2x = (2/6) = 1/3


How do you solve 6x squared equals negative 7x minus 2?

6x2 = -7x -2 6x2 + 7x + 2 = 0 6x2 + 3x + 4x + 2 = 0 3x(2x + 1) + 2(2x + 1) = 0 (2x + 1)(3x + 2) = 0 2x + 1 = 0 or 3x + 2 = 0 So, x = -1/2 or -2/3


How do you factor 3x-12x3?

-3x(2x - 1)(2x + 1)


How do you find the perimeter of 2x and 3x?

(2x x 3x) x 2 = 12x (2x times 3x times 2)


What is 2x squared add 3x?

5


What is 10 plus 2(x - 1) plus 7 x 3x plus 1?

10 + 2(x - 1) + 7 x 3x + 1 =10 + 2x - 2 + (7 x 3x) + 1 =10 + 2x - 2 + 21x + 1 =2x + 21x + 10 - 2 + 1 =23x + 9


5x3-3x plus 4 -3x3-2x2 plus 6x-1?

Am I right :P?5x^(3)-3x+4-3x^(3)-2x+6x-1Since 5x^(3) and -3x^(3) are like terms, add -3x^(3) to 5x^(3) to get 2x^(3).(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)-3x+4-2x+6x-1Since -3x and -2x are like terms, subtract 2x from -3x to get -5x.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)-5x+4+6x-1Since -5x and 6x are like terms, subtract 6x from -5x to get x.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)+x+4-1Subtract 1 from 4 to get 3.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)+x+3To find the derivative of 2x^(3), multiply the base (x) by the exponent (3), then subtract 1 from the exponent.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+(d)/(dx) x+3To find the derivative of x, multiply the base (x) by the exponent (1), then subtract 1 from the exponent (1-1=0). Since the exponent is now 0, x is eliminated from the term.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1+(d)/(dx) 3Since 3 does not contain x, the derivative of 3 is 0.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1+0Add 0 to 1 to get 1.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1The derivative of 5x^(3)-3x+4-3x^(3)-2x+6x-1 is 6x^(2)+1.6x^(2)+1


Solve-3x-2 equals 2x plus 4 for x?

3x - 2 = 2x + 4 3x - 2x = 4 + 2 x = 6