This is a Ditloid.
The answer is 1 step forward, 2 steps back.
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The next letter will be a "b." The pattern 2-1-3-2-4-3-etc. So the "a"s and "b"s will each increase by one. First there were two "b"s, then one "a." Then there were three "b"s and two "a"s. So next there will be four "b"s and three "a"s, five "b"s and four "a"s, and so on.
Assuming the sides of the triangle a=5, b=5 and c=6, the semiperimeter s=(5+5+6)/2=8. Height d=3 is not necessary if you use Heron´s formula for the area (A): A = [s(s-a)(s-b)(s-c)]1/2 = [8(8-5)(8-5)(8-6)]1/2 = [144]1/2 = 12
A set "A" is said to be a subset of "B" if all elements of set "A" are also elements of set "B".Set "A" is said to be a proper subset of set "B" if: * A is a subset of B, and * A is not identical to B In other words, set "B" would have at least one element that is not an element of set "A". Examples: {1, 2} is a subset of {1, 2}. It is not a proper subset. {1, 3} is a subset of {1, 2, 3}. It is also a proper subset.
B&F for Baden & Foss, NY, NY circa 1940-1950's I believe.
4 and 5 are co-prime so the smallest positive integer that is divisible by 4 and 5 is 4*5 = 20. Let S stand for the smallest positive integer that is divisible by 4, 5 and B.After that the answer depends on the value of BIf B is co-prime with both 4 and 5 then S = 20B.If B is co-prime with 4 but is a multiple of 5, then let B = 5*C. Then S = 20C.If B is a multiple of 4 but is co-prime with 5, then let B = 4*D. Then S = 20D.If B is a multiple of 2 but not 4, and is co-prime with 5, then let B = 2*E. Then S = 20E.If B is a multiple of 2 but not 4, and is also a multiple of 5, then let B = 10*F. Then S = 20F.If B is a multiple of 4 as well as of 5 then S = B.