p^2 x p^2 = p^4 p^2 + p^2 = 2p^2
p^3 ÷ p^2 = p^(3-2) = p^1 = p
2 P in a Q ' Two persons in a queue.
It is: p-2
for this we'll use the basic formula ie p = 2 (l+b) p = 2 (6+7) p = 2 (13) p = 26 where p is perimeter
p^2 x p^2 = p^4 p^2 + p^2 = 2p^2
p+2 = 2-3p p+3p = 2-2 4p = 0 p = 0
p^3 ÷ p^2 = p^(3-2) = p^1 = p
(p-2) x (p5) = p-2+5 = p3
p-2
p^2(p squared)
2 P in a Q ' Two persons in a queue.
Area of triangle = sqrt[p/2*(p/2-a)*(p/2-b)*(p/2-c)] where a, b and c are the sides.
If p = 2s + 5, then s = (p-5)/2 or 1/2 (p-5) --- p = 2s +5 p-5 = 2s (p-5)/2 = s
A prime triplet contains a pair of twin primes (p and p + 2, or p + 4 and p+ 6), a pair of cousin primes (pand p + 4, or p + 2 and p + 6), and a pair of sexy primes (p and p + 6).
2 peas in a pod
|p| = 2.