(p-2) x (p5) = p-2+5 = p3
The expression "p to the second power multiplied by five" can be written mathematically as ( 5p^2 ). This means you take the square of ( p ) (which is ( p \times p )) and then multiply that result by 5. So, the final answer is ( 5p^2 ).
The Answer Is 120 :P -Kris
p=1/3(A)^2 where: p=power A=maximun amplitude
Add the exponents: p2p7 = p9
The expression that represents two times the sum of p and 8 is 2(p + 8).
Oh, dude, you're hitting me with some math here! So, "p times p squared" is basically p multiplied by p squared, which is p to the power of 2. When you multiply p by p squared, you're essentially multiplying p by p to the power of 2, which gives you p to the power of 3. So, the answer is p cubed. Math can be fun... sometimes.
The expression "p to the second power multiplied by five" can be written mathematically as ( 5p^2 ). This means you take the square of ( p ) (which is ( p \times p )) and then multiply that result by 5. So, the final answer is ( 5p^2 ).
The correct formula for finding power in a DC circuit is ( P = V \times I ), where ( P ) represents power in watts, ( V ) is the voltage in volts, and ( I ) is the current in amperes. Additionally, power can also be calculated using ( P = I^2 \times R ) or ( P = \frac{V^2}{R} ), where ( R ) is the resistance in ohms. These formulas allow you to determine power based on different known quantities in the circuit.
Ah, what a happy little math problem we have here! When you see "p times p to the third power," you simply need to multiply p by p cubed. This gives you p to the power of 4, as you add the exponents when you multiply like bases. Just a joyful reminder to embrace mistakes as happy little accidents in your math journey!
The formula for power lost in an electrical circuit, primarily due to resistance, can be derived from Ohm's Law and the definition of power. Ohm's Law states that ( V = I \times R ), where ( V ) is voltage, ( I ) is current, and ( R ) is resistance. The power lost, or dissipated as heat, can be calculated using the formula ( P = I^2 \times R ) or ( P = \frac{V^2}{R} ), where ( P ) is power. This shows that power loss increases with the square of the current or inversely with the resistance.
The Answer Is 120 :P -Kris
The power consumed in a resistor can be calculated using the formula ( P = I^2 R ), where ( P ) is power, ( I ) is current, and ( R ) is resistance. In this case, with a current of 15 mA (or 0.015 A) flowing through a 10 ohm resistor, the power consumed is ( P = (0.015)^2 \times 10 = 0.00225 \times 10 = 0.0225 ) watts or 22.5 mW.
When you divide p cubed by p squared, you are essentially dividing p to the power of 3 by p to the power of 2. This simplifies to p^(3-2), which equals p^1. Therefore, the result of p cubed divided by p squared is p.
23p = 2*2*2*p=4*2*p= 8p
p=1/3(A)^2 where: p=power A=maximun amplitude
Add the exponents: p2p7 = p9
P=I^2*R where P=power I=Current R=Resistance