To find a two-digit number that is a multiple of both 3 and 4 and has digits that sum up to 15, we can start by listing the multiples of 3 and 4: 12, 24, 36, 48, 60, 72, 84, 96. Among these, the numbers that have digits summing up to 15 are 48 and 84. Therefore, the two-digit number that satisfies all the given conditions is 48.
There are an infinite number of multiples of 6 (numbers that six can divide into evenly with no remainder). Without using a calculator, you can determine if a number is a multiple of 6. To be a multiple of 6, it must have both 3 and 2 as factors. So if the number is even, then 2 is a factor. To determine if it is even, look at the ones digit, and if it is (0,2,4,6, or 8) then it's even. Then to determine if 3 is a factor, add the digits in the number, if this sum is a multiple of 3, then the number is also a multiple of 3 (or you could say 3 is a factor). If both of these are true, then the number is a multiple of 6. Example: 984: Last digit (ones digit) is 4, so it's even. Sum 9+8+4=21, which is a multiple of 3, so the number is a multiple of 3. Therefore it is a multiple of 6.
The greatest 3-digit number is 999. 9+9+9 = 27 The sum of the greatest 3-digit number is 27.
The units digit of a two digit number exceeds twice the tens digit by 1. Find the number if the sum of its digits is 10.
i am a two digit # my tens digit# is 3 times my ones digit #and the sum of my digit is 12 what am i
"If the units digit and the hundreds digit of the number 513 were reversed..." 315 'find the sum of the original number and the new number." 513+315=828
The question is a bit ambiguous: "the sum of the product ... " does not seem to make sense. The first 5 digit number is 10000 the first 5 digit multiple of 6 is 10002 Their product is 100020000. I am not sure what to sum, though.
If the number is even, it is a multiple of 2 If the sum of the digits make a number divisible by 3, the number is a multiple of 3 If the number ends in 5 or 0, the number is a multiple of 5 If the number is divisible by 2 and 3, the number is a multiple of 6 If the sum of the digits make a number divisible by 9, the number is a multiple of 9
No two digit prime number exists that is a multiple of 7. All two digit numbers that are multiples of 7 are compositenumbers.
Add the last digit (units digit) to twice the previous digit (tens digit). If this sum is divisible by 4, so is the original number.
8 and 1
96
96
96
The sum of 7 times the last digit and the rest of the number is a multiple of 23
The sum of 6 times the last digit and the rest of the number is a multiple of 59
The sum of 22 times the last digit and the rest of the number is a multiple of 73
The sum of 8 times the last digit and the rest of the number is a multiple of 79