To simplify the expression 2a^2b^2 + 5ab^2 + 8a^2b^2 - 3ab^2, first combine like terms. The terms with a^2b^2 are 2a^2b^2 + 8a^2b^2 = 10a^2b^2. The terms with ab^2 are 5ab^2 - 3ab^2 = 2ab^2. Therefore, the simplified expression is 10a^2b^2 + 2ab^2.
Assuming that non-leading numbers are exponents, the expression becomes12a^2b + 8a - 5a^2b + 2ab - 4ab^2 + 6ab - 2a - 3ab= 7a^2b + 6a + 5ab - 4ab^2= a*(7ab + 6 + 5b - 4b^2)
2a-3ab = -1
6a2 + 5ab - 6b2 = (3a - 2b)(2a + 3b)
(3a - 2b)(2a + 3b)
2a + a = 3a
Assuming that non-leading numbers are exponents, the expression becomes12a^2b + 8a - 5a^2b + 2ab - 4ab^2 + 6ab - 2a - 3ab= 7a^2b + 6a + 5ab - 4ab^2= a*(7ab + 6 + 5b - 4b^2)
2a-3ab = -1
No. 2a is one thing, 3b is another. If you add them together, they become 2a + 3b. 5ab indicates that multiplication has taken place. 5 times a times b = 5ab
6a2 + 5ab - 6b2 = (3a - 2b)(2a + 3b)
(a - 2b)(2a - b)
Considering the minus sign between 5ab and 6b2 then we have the polynomial as 6a2 + 5ab - 6b2. The polynomial is a quadratic polynomial.Steps to factorize a quadratic polynomial:1 - Multiply first term by third term. 6a2 x (-6b2) = -36a2b22 - If possible break the second term into two terms such that they multiple to -36a2b2. If not then it is factorized by Sridharacharya's formula.5ab can be broken as 9ab + (-4ab).These two terms multiply to give -36a2b2.So we can write 6a2 + 5ab - 6b2 = 6a2 + 9ab + (-4ab) - 6b2.6a2 + 9ab - 4ab - 6b2 = 3a(2a + 3b) - 2b(2a + 3b) = (2a + 3b)(3a - 2b).So the factors are (2a + 3b) and (3a - 2b).
(3a - 2b)(2a + 3b)
A=-4 b=5 2a=-8 2b=10 5ab=-100 2a x 2b x 5ab= -8000
a + a + a - 2a = 3a - 2a = a
2a + a = 3a
4a
What is the solution of -2a plus 3a plus 5b