6a2 + 5ab - 6b2 = (3a - 2b)(2a + 3b)
2a(3a - 4b + 1)
The given polynomial does not have factors with rational coefficients.
5ab-2ab+4a-b+5b = 3ab+4a+4b
35ab squared
6a2 + 5ab - 6b2 = (3a - 2b)(2a + 3b)
Considering the minus sign between 5ab and 6b2 then we have the polynomial as 6a2 + 5ab - 6b2. The polynomial is a quadratic polynomial.Steps to factorize a quadratic polynomial:1 - Multiply first term by third term. 6a2 x (-6b2) = -36a2b22 - If possible break the second term into two terms such that they multiple to -36a2b2. If not then it is factorized by Sridharacharya's formula.5ab can be broken as 9ab + (-4ab).These two terms multiply to give -36a2b2.So we can write 6a2 + 5ab - 6b2 = 6a2 + 9ab + (-4ab) - 6b2.6a2 + 9ab - 4ab - 6b2 = 3a(2a + 3b) - 2b(2a + 3b) = (2a + 3b)(3a - 2b).So the factors are (2a + 3b) and (3a - 2b).
(5ab^2 + 4cd)(5ab^2 4cd) <
The GCF of 5ab and 56b squared is b.
-3b2(5b - 2)
b2(b + 6)
5ab(3a - 2b)
3(2b2 - 5b - 2)
(-3b - 4)(-2b + 5)
8(8 - 5ab)
3a(2a + 1)
2a(3a - 4b + 1)