6a2 + 5ab - 6b2 = (3a - 2b)(2a + 3b)
2a(3a - 4b + 1)
To find the least common multiple (LCM) of 5ab and 7ab squared, we need to consider the highest power of each prime factor in both numbers. The prime factors in 5ab are 5, a, and b, while the prime factors in 7ab squared are 7, a, and b squared. The LCM will be the product of the highest power of each prime factor, which gives us 35ab squared.
The given polynomial does not have factors with rational coefficients.
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6a2 + 5ab - 6b2 = (3a - 2b)(2a + 3b)
Considering the minus sign between 5ab and 6b2 then we have the polynomial as 6a2 + 5ab - 6b2. The polynomial is a quadratic polynomial.Steps to factorize a quadratic polynomial:1 - Multiply first term by third term. 6a2 x (-6b2) = -36a2b22 - If possible break the second term into two terms such that they multiple to -36a2b2. If not then it is factorized by Sridharacharya's formula.5ab can be broken as 9ab + (-4ab).These two terms multiply to give -36a2b2.So we can write 6a2 + 5ab - 6b2 = 6a2 + 9ab + (-4ab) - 6b2.6a2 + 9ab - 4ab - 6b2 = 3a(2a + 3b) - 2b(2a + 3b) = (2a + 3b)(3a - 2b).So the factors are (2a + 3b) and (3a - 2b).
(5ab^2 + 4cd)(5ab^2 4cd) <
The GCF of 5ab and 56b squared is b.
-3b2(5b - 2)
3(2b2 - 5b - 2)
(-3b - 4)(-2b + 5)
5ab(3a - 2b)
8(8 - 5ab)
3a(2a + 1)
2a(3a - 4b + 1)
(2a - 1)(3a + 4)