x + 3 + 2x = x + 9 x + 2x + 3 = x + 9 1x - 1x + 2x + 3 = 1x - 1x + 9 1x - 1x + 2x + 3 = 1x - 1x + 9 2x + 3 = 9 2x + 3 - 3 = 9 - 3 2x + 3 - 3 = 9 - 3 2x = 9 -3 2x = 6 2x/2 = 6/2 2x/2 = 6/2 x = 6/2 x = 3
2x+3=9 x
5x=2x+27 subtract 2x from both sides get get X on only 1 side of the equation. 5x-2x=2x-2x + 27 leaves you with 3x = 27 divide both sides by 3 3x/3 = 27/3 leaves you with x = 9 answer X=9
2x-3=9 so 2x=12 and x=6
2x-3=4x+9 -2x-12=0 2x=-12 x=-6
x + 3 + 2x = x + 9 x + 2x + 3 = x + 9 1x - 1x + 2x + 3 = 1x - 1x + 9 1x - 1x + 2x + 3 = 1x - 1x + 9 2x + 3 = 9 2x + 3 - 3 = 9 - 3 2x + 3 - 3 = 9 - 3 2x = 9 -3 2x = 6 2x/2 = 6/2 2x/2 = 6/2 x = 6/2 x = 3
2x 3 9 x ?
2x+3=9 Your question is what is X value. 2x+3=9 2x=9-3 2x=6 2/2x=6/2 x=3 Best answer by Deo Math Club...
2x+3=9 2x=9-3 2x=6 2x/2=6/2 X=3
2x + 3 = 9. What you need to do first, is to isolate the 'x' by itself. Subtract the 3 to the other side. 2x + 3 = 9. (Before subtraction) 2x = 6 (After subtraction) Then you can divide by whatever is on the 'x'. In this case, it is 2. (Before) 2x = 6 (After) x = 3. Now you can check the problem, so put in 3 for x. 2x + 3 = 9. 2(3) + 3 = 9. 6 + 3 = 9. 9 = 9.
if 2x+3=9 then 2x=6 so x=3
common it's very easy !!2x + 3 = 92x = 6x = 6/2x = 3
2x+3=9 x
5x=2x+27 subtract 2x from both sides get get X on only 1 side of the equation. 5x-2x=2x-2x + 27 leaves you with 3x = 27 divide both sides by 3 3x/3 = 27/3 leaves you with x = 9 answer X=9
2x-3 = 9 2x = 9+3 2x = 12 x = 6
2x-3=9 so 2x=12 and x=6
3x2 + 2x + 2 = 0 Can not be factored. You can however solve it for x: 3x2 + 2x = -2 x2 + 2x/3 = -2/3 x2 + 2x/3 + 1/9 = -2/3 + 1/9 (x + 1/9)2 = -5/9 x + 1/9 = ±√(-5/9) x = -1/9 ± i√(5/9) x = -1/9 ± i√5 / 3 x = -1/9 ± 3i√5 / 9 x = (-1 ± 3i√5) / 9