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2x + 2y = 14 eqn 1
2x - y = 5 eqn 2
Solve for X and Y.
Simplify eqn 2 to solve for y
2x - y = 5
subtract sx from both sides
-y = 5 - 2x
multiple both sides by -1
y = 2x - 5
substitute 2x - 5 into eqn 1 for y
2x + 2y = 14
2x + 2(2x -5) = 14
2x + 4x - 10 = 14
6x - 10 = 14
add 10 to both sides
6x = 24
divide both sides by 10
x= 4
Substitute x = 4 into eqn 2
y = 2(4) - 5
y = 8 - 5
y = 3
X = 4 and y = 3
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If: 3x+2y = 5x+2y = 14 Then: 3x+2y = 14 and 5x+2y =14 Subtract the 1st equation from the 2nd equation: 2x = 0 Therefore by substitution the solutions are: x = 0 and y = 7
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