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What is the sum of the first 33 terms of the following sequence 8 17 26?
5016. Here's how: Each term is 1 less than the terms in 9, 18, 27 ..., which is the sequence 9*N, with N = 1..33. So the actual formula for the sequence is {9*N - 1} The sequence 1,2,3...N can be summed by (N+1)*N/2 --> N=33: (33+1)*33/2 = 561, so the sum of the first 33 terms of 9+18+27+297 = 9*(1+2+3+..+33) = 9*561 = 5049. But our sequence terms are each one less than the terms in 9,18,27, so subtract 33 from 5049 = 5016.
What are the next three terms in the sequence -3 6 15 24?
First, in order ro find the next three terms in the sequence, you must find out the sequence. To do so, take 24 and subtract 15, now take the answer and subtract it from 15, which should equal 6. The sequence or the difference between all the numbers is 9. Now that we know the sequence, we can answer the question. Lets take 24 and add 9 to it, we come out with 33, now take 33 and add 9, which is 42 and add 9 to that which gives you 51. The next three terms are 33, 42 and 51
Is 33 a multiple of 9?
No, 33 is not a multiple of 9.
Subtract 9x-9 from 2x plus 3?
You can only add or subtract like terms. So, you subtract 9x from 2x, which gives you -7x. Then subtract -9 from 3 to get -6. And you are left with -7x -6.
What is 33 take away 9?
33 - 9 = 24.
