0
5016. Here's how:
Each term is 1 less than the terms in 9, 18, 27 ..., which is the sequence 9*N, with N = 1..33.
So the actual formula for the sequence is {9*N - 1}
The sequence 1,2,3...N can be summed by (N+1)*N/2 --> N=33: (33+1)*33/2 = 561, so the sum of the first 33 terms of 9+18+27+297 = 9*(1+2+3+..+33) = 9*561 = 5049. But our sequence terms are each one less than the terms in 9,18,27, so subtract 33 from 5049 = 5016.
What else can I help you with?
The sum of the first 5 terms of an arithmetic sequence is 40 and the sum of its first ten terms is 155what is this arithmetic sequence?
a1=2 d=3 an=a1+(n-1)d i.e. 2,5,8,11,14,17....
Find the sum of the first 48 terms of an aritmetic sequance 2 4 6 8?
To find the sum of the first 48 terms of an arithmetic sequence, we can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum of the first n terms, a1 is the first term, and an is the nth term. In this case, a1 = 2, n = 48, and an = 2 + (48-1)*2 = 96. Plugging these values into the formula, we get: S48 = 48/2 * (2 + 96) = 24 * 98 = 2352. Therefore, the sum of the first 48 terms of the given arithmetic sequence is 2352.
What is the sum of the first 64 terms of the binary sequence?
A binary sequence is a sequence of [pseudo-]randomly generated binary digits. There is no definitive sum because the numbers are random. The sum could range from 0 to 64 with a mean sum of 32.
What is the sum of the first ten terms of the arithmetic sequence 4 4.2 4.4...?
49
What is the sum of the first 150 positive integers?
Find the sum of the first 11 terms in the sequence 3 7 11
What is the sum of the first 28 terms of this arithmetic sequence?
To find the sum of the first 28 terms of an arithmetic sequence, you need the first term (a) and the common difference (d). The formula for the sum of the first n terms (S_n) of an arithmetic sequence is S_n = n/2 * (2a + (n - 1)d). Once you have the values of a and d, plug them into the formula along with n = 28 to calculate the sum.
The sum of the first 5 terms of an arithmetic sequence is 40 and the sum of its first ten terms is 155what is this arithmetic sequence?
a1=2 d=3 an=a1+(n-1)d i.e. 2,5,8,11,14,17....
Find the sum of the first 48 terms of an aritmetic sequance 2 4 6 8?
To find the sum of the first 48 terms of an arithmetic sequence, we can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum of the first n terms, a1 is the first term, and an is the nth term. In this case, a1 = 2, n = 48, and an = 2 + (48-1)*2 = 96. Plugging these values into the formula, we get: S48 = 48/2 * (2 + 96) = 24 * 98 = 2352. Therefore, the sum of the first 48 terms of the given arithmetic sequence is 2352.
What are the terms of a sequence added together?
The terms of a sequence added together is the sum.
What is the sum of the first 64 terms of the binary sequence?
A binary sequence is a sequence of [pseudo-]randomly generated binary digits. There is no definitive sum because the numbers are random. The sum could range from 0 to 64 with a mean sum of 32.
What is the sum of the first 50 terms of the sequence an equals 3n plus 2?
3925
Why did Fibonacci find his sequence so interesing?
because you add the first 2 terms and the next tern was the the sum of the first 2 terms.
What is the sum of the first ten terms of the arithmetic sequence 4 4.2 4.4...?
49
What is the sum of the first 150 positive integers?
Find the sum of the first 11 terms in the sequence 3 7 11
What is the sum of the first 12 terms of the arithmetic sequence?
The sum of the first 12 terms of an arithmetic sequence is: sum = (n/2)(2a + (n - 1)d) = (12/2)(2a + (12 - 1)d) = 6(2a + 11d) = 12a + 66d where a is the first term and d is the common difference.
What is the sum of first six terms of a sequence whose nth term is 8 - n?
nth term is 8 - n. an = 8 - n, so the sequence is {7, 6, 5, 4, 3, 2,...} (this is a decreasing sequence since the successor term is smaller than the nth term). So, the sum of first six terms of the sequence is 27.
Can you find the sum of the terms in an infinite sequence?
yup
