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Since r varies directly with s, we have r = ks (replace k with 5 and s with 7) r = (5)(7) r = 35
pq-r, if p is 3, q is 4, and r is -6 is equal to 3 x 4 - (-6), which is equal to 12 + 6, which is equal to 18.
r and s can be any values such that r + s = 39. The answer is indeterminate since there are many solutions for that expression. If the new expression is included, then there must be some r and s for the problem.
P=s r t , so, s= P/(st)
R = S + 2T S = 3T .... substitute R = (3T) + 2T R = 5T
15 and 24, respectively.
if r=5z and 15z =3 then r=10y
If 'r' and 's' can be the same integer, then (1)3 = (1)2 , and k = 1 .If 'r' and 's' must be different integers, then (4)3 = (8)2 , and k = 64 .
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Since r varies directly with s, we have r = ks (replace k with 5 and s with 7) r = (5)(7) r = 35
r = 5z 15z = 3y (divide by 3 to both sides) 5z = y r = y
3 equals rings in a circus
Square root of s, or negative square root of s.
If Q = R/S then R = QxS and S = R/Q You can easily replace the letters with numbers such as Q = 2, R = 6 and S = 3 and then write out all three equations and you'll see that they make sense.
500 equals: Sheets in a ream.
pq-r, if p is 3, q is 4, and r is -6 is equal to 3 x 4 - (-6), which is equal to 12 + 6, which is equal to 18.