x/2 + 1/3 = (x/2)(3/3) + (1/3)(2/2) = 3x/6 + 2/6 = (3x + 2)/6
x/2 - 7 = -10 x/2 = -3 x = -3 x 2 x = -6
b/6
(x^3 + 2x^2 + 3x - 6)/(x - 1) add and subtract x^2, and write -6 as (- 3) + (-3) = (x^3 - x^2 + x^2 + 2x^2 - 3 + 3x - 3)/(x - 1) = [(x^3 - x^2) + (3x^2 - 3) + (3x - 3)]/(x - 1) = [x^2(x - 1) + 3(x^2 - 1) + 3(x - 1)]/(x - 1) = [x^2(x - 1) + 3(x - 1)(x + 1) + 3(x - 1)]/(x - 1) = [(x - 1)(x^2 + 3x + 3 + 3)]/(x - 1) = x^2 + 3x + 6
6.
(1/3) x (2/2) x (3/6) = 1/6
x/2 + 1/3 = (x/2)(3/3) + (1/3)(2/2) = 3x/6 + 2/6 = (3x + 2)/6
You didn't say what it was over; so the answer is no unless it is over x, where 2 + 3/x = 2.6 Solve for x. 3/x = 2.6 - 2= 0.6 = 6/10 x/3 = 10/6 x = 30/6 = 5
If 2/x + 1/3 = 4/x,multiply each term by 3x, then 6 + x = 12.Subtracting 6 from each side, x = 6.Verifying left side by substituting 6 for x, 2/6 + 1/3 = 1/3 + 1/3 = 2/3;verifying right side by substituting 6 for x, 4/6 = 2/3.
3/2 x 1/9 = 3/18 (1/6.)
6 = 2 x 3 8 = 2 x 2 x 2 LCM = 2 x 2 x 2 x 3 = 24
x=2
2/3 is equivalent to 4/6 (2 x 2 =4, 3 x 2 = 6). 4/6 is 4 days.
6 / ( x + 4 ) = 2 / 3 1 - Multiply both parts by 3 3 * 6 / ( x + 4 ) = 2 2- Multiply both parts by (x+4) 3 * 6 = 2 * ( x + 4 ) 3 - Simplify 18 = 2x + 8 10 = 2x 5 = x
If: 4/6 = x/3 Then: x = 2
x={3, -5} This is if the equation is: 5/(x+2) = x/3. But if you wanted: (5/x) + 2 = x/3, that is different, then x = 3±2*sqrt(6)
2/6 x 3/5 = 6/30 = 1/5