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Is a over b over c equal to ac over b?
No. Assuming no parentheses, a/b/c = (a/b)/c = a/bc. For example, 1/2/3 = (1/2)/3 = 1/6. If there are parentheses for the last 2 terms, such as a/(b/c), then it is ac/b. Similarly, if you see it written out as a complex fraction with the a on the top half and the b/c in the bottom half, then it is the same as ac/b.
What is the answer of a over b when a is 2 over 3 and b is 3 over 4?
8/9
Is a to the second power over b to the second power greater than a over b?
Let's reverse the question - Is a over b less than a squared over b squared? Answer - Only when a is less than b example 1: a is less than b a = 2 a squared = 4 b = 3 b squared = 9 2 / 3 = .6666 4 / 9 = .444444 2 / 3 is greater than 4 / 9 example 2: a is equal to b a = 2 a squared = 4 b = 2 b squared = 4 2 / 4 = .5 2 / 4 = .5 2 / 4 is equal to 2 / 4 example 3: a is greater than b a = 3 a squared = 9 b = 2 b squared = 4 3 / 2 = 1.5 9 / 4 = 2.25 3 / 2 is less than 9 / 4 - wjs1632 -
Why isnt subtraction commutative?
Example: a - b = b-a, So lets say a=2 b=3. 2-3=3-2 -1 =/= 1
Circumference of an oval?
There is no simple answer: in fact the search for the answer led to the study of elliptical integrals.C = 2*pi*a*{1 - [1/2]^2*e^2 + [(1*3)/(2*4)]^2*e^4/3 - [(1*3*5)/(2*4*6)]^2*e^6/5 + ... }wherea is the semi-major axis,b is the semi-minor axis, ande is the eccentricity = sqrt{(a^2 - b^2)/a^2}.The above infinite series converges very slowly.An approximation, suggested by Ramanujan, isC = pi*{3(a + b) - sqrt[(3a + b)*(a +3b)]} = pi*{3(a + b) - sqrt[10ab + 3(a^2 + b^2)]}
