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Anonymous
3a2 - 16a + 5
= 3a2 - 15a - a + 5
= 3a(a -5) - 1(a -5)
= (3a - 1)(a - 5)
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9(x-3)=3(2x+4)
25a2-30a+9
(5a-3)^2
2(5a - 2)(5a - 2) or 2(5a - 2)2
(x + 4)(4x - 1)
5(2r + 5)
5(2g + 7h)
(x + 3)(4x + 5)
5(4x - 3)(2x + 5)
(x + 5)(x + 5)