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How can you find the sum of 2z-20 and 3z plus 5?
Add like terms to like: (2z - 20) + (3z + 5) = (2z + 3z) + (-20 + 5) = 5z - 15 2z is shorthand for z+z, 3z is shorthand for z+z+z, so: 2z + 3z = (z+z) + (z+z+z) = z+z+z+z+z = 5z Or, to put it another way, just add the coefficients: 2z + 3z = (2+3)z = 5z.
How do you find the sum of 3z 2 z equals 5?
Since you say you are looking for the sum, I will assume that the equation that you should have written is 3z + 2 + z = 5.3z + 2 + z = 53z - 2 + z = 5 -23z + z = 34z = 34z/4 = 3/4z = 3/4This is very correct.you are a mathematician
What is 3z divided by 2 which equals 9?
If 3z/2 = 9 then the value of z is 6
Subtract 5 from 3 times z?
3z - 5
Marcia has 84 less than three times as much as Sue together they have 132 how much money does Marcia have?
Sue has Z. Marcia has (3Z - 84), three times as much as Sue, minus 84. Together their amounts equal 132. So, The amount Sue has plus the amount Marcia has is 132 or, Z + (3Z - 84) = 132 Then, Z + 3Z = 132 + 84 (minus 84 from one side of the expression, and add it to the other side) Z + 3Z = 216 (Z + 3Z)/Z = 216/Z (divide both sides by Z to get one Z on one side) Z/Z + 3Z/Z = 216/Z (or written like this) 1 + 3 = 216/Z 4 = 216/Z 4 x Z = (216/Z) x Z (multiply both sides by Z) 4Z = 216 4Z/4 = 216/4 (divide by 4 to isolate Z) Z = 54 So, Sue has 54, therefore if Marcia has (3Z - 84), then 3 x 54 - 84, which is 78. So, Marcia has 78 We can check that together, 54 plus 78 equals 132.
