If 3z/2 = 9 then the value of z is 6
Add like terms to like: (2z - 20) + (3z + 5) = (2z + 3z) + (-20 + 5) = 5z - 15 2z is shorthand for z+z, 3z is shorthand for z+z+z, so: 2z + 3z = (z+z) + (z+z+z) = z+z+z+z+z = 5z Or, to put it another way, just add the coefficients: 2z + 3z = (2+3)z = 5z.
3z+2= x ; z=53(5)+215+217Blake watson 63877
The sum of the digits in 252 is 2 + 5 + 2 which equals 9.
change the equation around 4x-6=2 becomes 4x=2+6
Collect all the letters on one side and the numbers on the other; what you do to one side of the equals you do to the other: 3z + 2 = 6z - 13 → 3z +2 - 3z = 6z - 13 - 3z → 2 = 3z - 13 → 2 + 13 = 3z - 13 + 13 → 15 = 3z → 3z = 15 (this is just changing the equals around so that the letter is on the left) → 3z ÷ 3 = 15 ÷ 5 → z = 5
-47 + 6z = 3z-2-3z -3z-47 + 3z = -2+47 +473z = 45/3 /3z = 15
If 3z/2 = 9 then the value of z is 6
-6z 2 = 3z+ 4z+28 -6z+2 +3z = 3z+ 4z +28 +4z -6z+4z+2 = 3z+ 28 -10z+2 -3z= 28 - 2 -10z + -3z = 26 -13z/13 = 26/-13 z = -2
It's rare to see an equation with two equals signs. I'm guessing something else went in between 3z and 9. 3z + 9 = 15, then z = 2 3z - 9 = 15, then z = 8 3z x 9 = 15, then z = 5/9 3z/9 = 15, then z = 45
-3z+17+12z = 11 9z = -6 z = -2/3
-6z + 2 = 3z + 4z + 28 Add 6z to both sides: 2 = 3z + 4z + 28 + 6z = 28 + 13z Subtract 28 from both sides: - 26 = 13z Divide both sides by 13: -2 = z
Add like terms to like: (2z - 20) + (3z + 5) = (2z + 3z) + (-20 + 5) = 5z - 15 2z is shorthand for z+z, 3z is shorthand for z+z+z, so: 2z + 3z = (z+z) + (z+z+z) = z+z+z+z+z = 5z Or, to put it another way, just add the coefficients: 2z + 3z = (2+3)z = 5z.
-3/2
The sum of a single number is itself. So the only number whose sum equals 2 is 2.
(3z-2)^2=4
The numbers are 7 and 6