To find a 4-digit number that is divisible by both 5 and 7, we need to find the least common multiple of 5 and 7, which is 35. The smallest 4-digit number divisible by 35 is 1005 (35 x 29 = 1005). The largest 4-digit number divisible by 35 is 9945 (35 x 284 = 9945). Therefore, the 4-digit numbers divisible by both 5 and 7 range from 1005 to 9945.
The smallest number that is divisible by 5, 6, and 7 is 210.
840 is the smallest number that is divisible by 5 6 7 and 8.
If a number is divisible by 5 and 7, it's divisible by 35.
1, 2, 4, 5, 7, 8
For a number to be divisible by 105 it must be divisible by 3, by 5 and by 7. So, divisibility by 3 requires all three of the following to be satisfied:Sum the digits together. Repeat if necessary. If the answer is 0, 3, 6 or 9 the original number is divisible by 3.If the final digit of the number is 0 or 5, the original number is divisible by 5.Take the number formed by all but the last digit. From it subtract double the last digit. Keep going until there is only one digit left. If it is 0 or 7 then the original number is divisible by 7.
The smallest number that is divisible by 5, 6, and 7 is 210.
840 is the smallest number that is divisible by 5 6 7 and 8.
19 divisible by 5, 14 divisible by 7. Of these, 3 divisible by both.
If a number is divisible by 5 and 7, it's divisible by 35.
210
No, 55557 is not divisible by 5. To be divisible by 5, the last digit must be 0 or 5. The last digit of 55557 is 7, and 7 is neither 0 nor 5, thus 55557 is not divisible by 5
The smallest number divisible by 5 7 9 11 13 and 15 is 45,045.
7 is not divisible by any of them.
No, 1017 is not divisible by 5. A number is divisible by 5 only if its last digit is 0 or 5. Since the last digit of 1017 is 7, it is not divisible by 5
'121'. 121/3 = 40.3333..... Not divisible. 121/5 any number that does not end in '5' or '0' is not divisible by '5' 121/7 = 17 3/7 Not divisible. 121/9 any number whose digits do not sum to nine is not divisible by '9' ; 1+2+1 = 4
5678 \
210