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How do you take 40 percent off of a price?
a = variable b = 40%a a - b = c
Two numbers have a sum of 40 the difference is 10 what are the two numbers?
2 Numbers are a and b. We have( a>b) a+b=40(1) and a-b=10(2) a=10+b( from 2. Subtracts both side by b) => 10+b+b=40 (from 1. Substitute a with 10+b) => 10+2b =40 => 2b =30 => b =15 =>a=10+15=25 => a=25 b=15.
If b equals a plus 40 and 2a plus 2b equals 160. solve for a and b?
2a + 2b = 160 But b = a + 40 so 2a + 2(a + 40) = 160 ie 2a + 2a + 80 = 160 or 4a = 80 ie a = 20 Then b = a + 40 gives b = 20 + 40 = 60 Solution: a = 20, b = 60
Transpose a-t divided by b-t equals c so that t is the subject?
(a - t)/(b - t) = c => a - t = c(b - t) = cb - ct = bc - tc => tc - t = bc - a => t(c - 1) = bc - a => t = (bc - a)/(c - 1)
What is the sets of base and height measurements for parallelograms with areas of 40 square units?
There are infinitely many possible answers. Select any number B and let H = 40/B Then a parallelogram with base B and height H has an area of B*H = B*40/B = 40 square units. Since the choice of B was arbitrary, there are an infinity of possible answers.
