0
Judges in the X Factor
Wiki User
∙ 14y ago
Add your answer:
Earn +20 pts
What polynomial function below find F(-4) f(x)2x2-x plus 9?
f(x) = 2 * 2 - x + 9 f(-4) = 2 * 2 -(-4) + 9 f(-4) = 4 + 4 + 9 = 17
Which equation represents an exponential function that passes through the point (2 36) (x) 4(3)x f(x) 4(x)3 f(x) 6(3)x f(x) 6(x)3?
It is f(x) = 4*3^x.
What is the inverse of f of x equals 5x plus 4?
No, f(x) is not the inverse of f(x).
What is the inverse of the function f(x) 4x?
if f(x) = 4x, then the inverse function g(x) = x/4
What is the value of the function f(x)3(4-x) when x7?
When x = 7, f(x) = 3*(4-x) = 3*(-3) = -9
When was J. F. X. O'Brien born?
J. F. X. O'Brien was born in 1828.
When did J. F. X. O'Brien die?
J. F. X. O'Brien died in 1905.
What has the author F X J D'Ambrosio written?
F. X. J. D'Ambrosio has written: 'Prepare or deter?'
Write a program to obtain transpose of a 4 X 4 Matrix in c using functions?
void main() { int arr[4][4]; int i,j,a,b,f; printf("\nInput numbers to 4*4 matrix"); for(i=0;i<4;i++) { for(j=0;j<4;j++) { printf("\nKey in the [%d][%d]) value",i+1,j+1); scanf("%d",&arr[i][j]); } } for(i=0;i<4;i++) { for(j=0,f=0;j<4;j++) { if(i!=j&&f==0) continue; a=arr[i][j]; b=arr[j][i]; arr[i][j]=b; arr[j][i]=a; f=1; } } for(i=0;i<4;i++) { for(j=0;j<4;j++) printf("%d ",arr[j][i]); printf("\n"); } }
If f(x)=6x -4, what is f(x) when x = 8?
f(x) =6x-4 f(x) = 6(8)-4 f(x) =48-4 f(x) =44
6. Let j(x) = x^2 − 2x + 4. Evaluate the following.j(a) =j(3)=j(x^2) =j(x + 3) = j(x + h) =?
A.) j(a) = a^2 - 2a + 4 B.) j(3) = (3)^2 - 2(3) + 4 = 9 - 6 + 4 = 7 C.) j(x^2) = (x^2)^2 - 2(x^2) + 4 = x^4 - 2x^3 + 4 D.) j(x+3) = (x + 3)^2 - 2(x + 3) + 4 = x^2 +6x + 9 - 2x - 6 + 4 = x^2 + 4x + 7 E.) j(x+h) = (x + h)^2 - 2(x + h) + 4 = x^2 + 2hx + h^2 - 2x - 2h + 4
What function has a vertex at the origin f(x) (x plus 4)2 f(x) x(x and ndash 4) f(x) (x and ndash 4)(x plus 4) f(x) and ndashx2?
It is f(x) = -x2 or (-x)2, whichever you intended.
What has the author J F X Hoery written?
J. F. X. Hoery has written: 'Banjire wis surut' 'Wuludomba pancal panggung'
Let j(x) = x^2 − 2x + 4. Evaluate the following.(a) j(a)(b) j(3)(c) j(x^2)(d) j(x + 3)(e) j(x + h)?
A.) j(a) = a^2 - 2a + 4 B.) j(3) = (3)^2 - 2(3) + 4 = 9 - 6 + 4 = 7 C.) j(x^2) = (x^2)^2 - 2(x^2) + 4 = x^4 - 2x^3 + 4 D.) j(x+3) = (x + 3)^2 - 2(x + 3) + 4 = x^2 +6x + 9 - 2x - 6 + 4 = x^2 + 4x + 7 E.) j(x+h) = (x + h)^2 - 2(x + h) + 4 = x^2 + 2hx + h^2 - 2x - 2h + 4
Let j(x) = x^2 − 2x + 4. Evaluate the following. (A) j(a). (B) j(3). (C) j(x^2). (D) j(x + 3). (E) j(x + h)?
A.) j(a) = a^2 - 2a + 4 B.) j(3) = (3)^2 - 2(3) + 4 = 9 - 6 + 4 = 7 C.) j(x^2) = (x^2)^2 - 2(x^2) + 4 = x^4 - 2x^3 + 4 D.) j(x+3) = (x + 3)^2 - 2(x + 3) + 4 = x^2 +6x + 9 - 2x - 6 + 4 = x^2 + 4x + 7 E.) j(x+h) = (x + h)^2 - 2(x + h) + 4 = x^2 + 2hx + h^2 - 2x - 2h + 4
How a function is even and odd?
The only way a function can be both even and odd is for it to ignore the input, i.e. for it to be a constant function. e.g. f(x)=4 is both even and odd. An even function is one where f(x)=f(-x), and an odd one is where -f(x)=f(-x). This doesn't make sense. Let's analyze. For a function to be even, f(-x)=f(x). For a function to be odd, f(-x)=-f(x). In this case, f(x)=4, and f(-x)=4. As such, for the first part of the even-odd definition, we have 4=4, which is true, making the function even. However, for the second part of it, we have 4=-4 (f(-x)=4, but -f(x)=-4), which is not true. Therefore constant functions are even because f(-x)=f(x), but not odd because f(-x)!=-f(x).
What is the combinationF(x)x2 and g(x)4-x?
if f(x) = x² and g(x) = 4 - x, then: fg(x) = (4 - x)² = 16 - 8x + x2 gf(x) = 4 - x² (f+g)(x) = x² + 4 - x (f - g)(x) = x² - 4 + x (fg)(x) = 4x² - x³ (f/g)(x) = x²/4 - x (iff x ≠ 4)
