Q: 4 pairs of numbers with a difference of 27?

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36/9 = 4 36 - 9 = 27 The two numbers are therefore 9 and 36.

The numbers are 27 and 23

This is not possible, 27 is an odd number, 4 odd numbers will always equal an even number.

32 -(1+4) =27

8 - 4 = 4

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Numbers. i^n = i^(n mod 4). With n = 27, 27 mod 4...

36/9 = 4 36 - 9 = 27 The two numbers are therefore 9 and 36.

The numbers are: 27 and 23

The numbers are 27 and 23

The difference is between factor pairs and distinct factors. With square numbers, one of the factor pairs will be the same number twice. When listing the distinct factors, that number is only listed once.

Any multiples of 4 that differ by 4.

4 and any multiple of 4 have a GCF of 4.

4

122

If it's a linear function, 3 should do, but 4 will give an extra check on you work. If the function is quadratic exponential, etc. then at least 4 pairs should be used.

27/4 is equal to 6 3/4

(4,8) and (8,12) both have a GCF of 4.