2x + 3y = 29x= 4 find x 29x= 4 x = (4/29) sub x into the first part of the sum 2x + 3y = 4 2*(4/29) + 3y = 4 note * means multiply (8/29) + 3y = 4 3y = 4 - (8/29) 3y = (108/29) note 4* 29 minus 8 = 108 y = (36/29) there is probably a quicker way to do this.
4 x 7 x 1 = 28... 28 + 1 = 29.
14, 19, 29, 44, 64, etc. 14 + (5 x 1) = 19 19 + (5 x 2) = 29 29 + (5 x 3) = 44 44 + (5 x 4) = 64
1 x 29, 29 x 1.
116 x 1 = 116 58 x 2 = 116 29 x 4 = 116
29 x 4 = 116
2x + 3y = 29x= 4 find x 29x= 4 x = (4/29) sub x into the first part of the sum 2x + 3y = 4 2*(4/29) + 3y = 4 note * means multiply (8/29) + 3y = 4 3y = 4 - (8/29) 3y = (108/29) note 4* 29 minus 8 = 108 y = (36/29) there is probably a quicker way to do this.
4 x 7 x 1 = 28... 28 + 1 = 29.
2 x 986 4 x 493 17 x 116 29 x 68 34 x 58 2 x 2 x 493 2 x 17 x 58 2 x 29 x 34 4 x 17 x 29 2 x 2 x 17 x 29
The factors of 116 are 1, 2, 4, 29, 58, and 116. The prime factors of 116 are 2 x 2 x 29.The prime factors of 116 are 2 x 2 x 29.
26x-4 = 25 +4 +4 26x = 29 x= 29/26 or 1.115...
1 x 232, 2 x 116, 4 x 58, 8 x 29, 29 x 8, 58 x 4, 116 x 2, 232 x 1.
There are 4 quarts in a gallon. Therefore, 29 gallons is equal to 29 x 4 = 116 quarts.
61 + 16 + 4 + (a string of 29 ones) = 110 61 x 16 x 4 x (a string of 29 ones) = 3904
The LCM of 29 and 116 is 116. 29 is a prime number, and 116 = 2 x 2 x 29, so you multiply these factors, excluding one occurrence of the common 29, i.e. 29 x 2 x 2, which is 116 which is the LCM (4 x 29, 1 x 116)
1 x 116, 2 x 58, 4 x 29.
7 with 1 remaining 29 - 1 = 28 = 4 x 7