14, 19, 29, 44, 64, etc.
14 + (5 x 1) = 19
19 + (5 x 2) = 29
29 + (5 x 3) = 44
44 + (5 x 4) = 64
As given, the sequence is too short to establish the generating rule. If the second term was 19 and NOT 29, then the nth term is tn = 6*n + 7 or 6(n+1)+1
This appears to be two interwoven sequences. The first sequence, increases by 9 then 19......7 + 9 = 16........8 + 19 = 27 The second sequence decreases by 8 then 18....16 - 8 = 8........27 - 9 = 18 The next number would thus be 9 + 29 = 38.
Difference means minus the two numbersie. 29 - 14 = 15This means that the difference is 15.
the sum of -14 + 29 is 15
42 is the next number in this sequence. This number sequence is adding the next prime number to the last number. So 1 + 2 = 3. Then 3 + 3 = 6, 6 + 5 = 11, 11 + 7 = 18, 18 + 11 = 29. The next prime number after 11 is 13, so 29 + 13 = 42. The next numbers would be 59 (42+17), 78 (59+19), and 101 (78+23)
The first number in the sequence 19, 23, 29, 31 is 19. This sequence lists prime numbers, and 19 is the smallest among them.
39
14, 19, 29, 40, 44, 52, 59, 73... 1+4= 5 , 14 + 5 = 19 1+9= 10 , 19 + 19 = 29 2+9= 11 , 29 + 11 = 40 . . . . It goes on :)
18 + 19 + 14 + 29 + 35 = 115/5 = 23
(15 + 19)/2 = 17
29
41
The sequence given is an arithmetic sequence where the first term is -29 and the common difference is 8 (calculated as -21 - (-29)). To find the 7th term, we can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ). Substituting ( a_1 = -29 ), ( d = 8 ), and ( n = 7 ), we get ( a_7 = -29 + (7-1) \cdot 8 = -29 + 48 = 19 ). Thus, the 7th term is 19.
dale pA la pinga
14.6552
29
23 21 (33 or 19)