First arrange this simultaneous equation in the form of:
4x+5y = 33
4x-2y = -2
Subtract the bottom equation from the top equation remembering that a - - is equal to a +:
7y = 35
Divide both sides by 7 to find the value of y:
y = 5
Substitute the value of y into the original equations to find the value of x:
So: x = 2 and y = 5
2y = 4x + 4y = 2x + 2
4x+2y-8=0 2y=8-4x y=4-2x slope= -2
x = -8, y = 10
-4x=2y-16 +16 +16 (-4x+16)=(2y) /2 /2 y=-2x+8
X = -2(13 + y) / 3x = 5y / 4 - 1
2y = 4x + 4y = 2x + 2
4x+2y=24 => 2y=24-4x => y=12-2x and the slope is -2
4x+2y = 20 2y = -4x+20 y = -2x+10
8x+2y=4x=-y/4+0.5y=-4x+2
-4x-2y = 3 -2y = 4x+3 y = -2x-1.5 which is the equation of a straight line
what is the slope of the line that has the equation 4x+2y=12?
4x + 2y = 6 (first equation x 2) 4x + 2y = 6 (second equation rearranged) No unique answer exists
-2
4x+2y-8=0 2y=8-4x y=4-2x slope= -2
4x+2y = 6 2y = -4x+6 y = -2x+3 Slope = -2
No.
4x + 2y = -8 → 2y = -4x - 8 → y = -2x - 4