I assume you're solving for x in the following equation:
4x2 - 32 = 4
To find the solution, start by adding 32 to both sides, so that the constant is on the right:
4x2 = 36
Next, divide both sides by 4, so you have x alone on the left side:
x2 = 9
So, x is going to be the square root of 9. Since x2 = (-x)2, there are two solutions: one positive, and one negative. 3 squared equals 9, so the two answers are -3 and 3.
7x2 -4x -5x2 +2x = 2x2 -2x
x2-10 = 4x+11 x2-4x-10-11 = 0 x2-4x-21 = 0 (x+3)(x-7) = 0 x = -3 and x = 7
4x2 - x - 5 = 0 4x2 + 4x - 5x - 5 = 0 4x(x + 1) - 5(x + 1) = 0 (4x - 5)(x + 1) = 0 4x - 5 = 0 or x + 1 = 0 4x = 5 or x = -1 x = 5/4 o x = -1
It equals 53X- a number is squared when it is multiplied by itself, so 7X by 7X = 49X. 2X by 2X =4X, so 49X + 4X is 53X.
4x - 7 = 5 + 7x x = -4
sqrt(4x+7) -4 = sqrt(4x-1) squared : (sqrt(4x+7) -4)2 = 4x-1 (4x+7) - 2x4xsqrt(4x+7) +16 = 4x-1 -8xsqrt(4x+7) = -24 sqrt(4x+7) = -24/-8 = 3 squared : 4x+7 = 32 = 9 4x = 9-7 = 2 then x=1/2
7x2 -4x -5x2 +2x = 2x2 -2x
(4x-5)(4x+5)
4x + 20
7
-x2+2x
(4x2) (x/4)(8x - 32) =x3(8x - 32) = 8x3(x - 4)
x2 - 4x - 21 = (x-7)(x+3)
Yes and x = 2+square root of 6 or x = 2-square root of 6
4x times 4x equals 16x2.
4x2 - 20 = 0∴x2 - 5 = 0∴x2 = 5∴x = √5
13