x2 - 4x - 21 = (x-7)(x+3)
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2x(2x - 1)
(2x - 1)(4x + 1)
4(x - 1)(x + 1)
(4x - t2)= [(2√x)2 - t2] (This is now the difference of squares)= (2√x - t)(2√x + t)
4x2+4x-8 4(x2+x-2) and (4x+8)(x-1)