X2 + 44x + 43
2X - 3 = 13 add 3 to each side 2X = 16 divide both sides by 2 X = 8 check 2(8) - 3 = 13 13 = 13 checks
the series is 2n+3 with n being the previous number 2(5)+3=13 2(13)+3=29 2(29)+3=61 2(61)+3=125 2(125)+3=253<----answer
1+1=2 1+2=3 2+3=5 ... 8+13=21
The prime factors of 6 are 2 and 3. The prime factors of 8 are 2, 2, and 2. The prime factors of 13 are 13. From 6, we have factors 2 and 3. From 8, we have 2, 2, and 2, but we already have one 2 from the factors of 6, so we only need to include two more 2s. So, now we have 2, 3, 2, and 2. From 13, we have the factor of 13. So, to determine the least common multiple, multiply 2 x 3 x 2 x 2 x 13 = 312. Double check: 312 ÷ 6 = 52 which is 13 x 2 x 2 312 ÷ 8 = 39 which is 13 x 3 312 ÷ 13 = 24 which is 2 x 2 x 2 x 3 There are no common prime factors for the three quotients, so 312 is confirmed as the least common multiple.
55x + (-3) = 53x + 7can be written as55x - 3 = 53x + 7subtract 53x from both sides2x - 3 = 7add three to both sides2x = 10divided both sides by 2x = 5
8-9x = 143-44x 44x-9x = 143-8 35x = 135 x = 135/35 = 22/7 or 3.'857142' recurring decimals
3x-1+10 = 53x + 9 = 53x = 5 - 93x = -4x = -4/3
Assuming you mean 3x - 2 = 9x - 5...3x - 2 = 9x - 53x + 3 = 9x3 = 6x0.5 = x
X2 + 44x + 43
8x3 + 12x2 - 44x - 24 = 4(2x3 + 3x2 - 11x - 6) = 4(2x3 - 4x2 + 7x2 - 14x + 3x - 6) = 4[2x2(x - 2) + 7x(x - 2) + 3(x - 2)] = 4(x - 2)(2x2 + 7x + 3) = 4(x - 2)(2x2 + 6x + x + 3) = 4(x - 2)[2x(x + 3) + 1(x + 3)] = 4(x - 2)(x + 3)(2x + 1)
HaHa ofcourse it does who wouldn't get HORN3Y
Prime factors are 2, 2, 3, 3, 3, 13 (Other) Factors are combinations of the above, i.e. 2 x 2 = 4 2 x 3 = 6 2 x 13 = 26 3 x 13 = 39 2 x 2 x 3 = 12 2 x 2 x 13 = 52 2 x 3 x 3 = 18 2 x 3 x 13 = 78 3 x 3 x 13 = 117 2 x 2 x 3 x 3 = 36 2 x 2 x 3 x 13 = 156 2 x 3 x 3 x 13 = 234 3 x 3 x 3 x 13 = 351 2 x 2 x 3 x 3 x 3 = 108 2 x 2 x 3 x 3 x 13 = 468 2 x 3 x 3 x 3 x 13 = 702
the answer is x=8/5 and x=4/3 from: Scott Powell
Factor into primes: 54 = 2*3*3*3 78 = 2*3*13 96 = 2*2*2*2*2*3 What product includes all of the above? You need five 2's, three 3's, and one 13 2*2*2*2*2*3*3*3*13 = 32*27*13 = 11,232
Since 13 is prime and 18=2*3*3, the LCD would be 2*3*3*13, or 234
3 = 3 13 = 13 14 = 2 x 7 LCM = 2 x 3 x 7 x 13 = 546