X2 + 44x + 43
7 fractions which are equivalent to 3/13 = 6/26, 9/39, 12/52, 15/65, 18/78, 21/91, 24/104,... To get the equivalent fractions of 3/13: Multiply 3/13 by 2/2, 3/3, 4/4, 5/5,... 3/13 * 2/2 = 6/26 3/13 * 3/3 = 9/39 3/13 * 4/4 = 12/52 3/13 * 5/5 = 15/65
2X - 3 = 13 add 3 to each side 2X = 16 divide both sides by 2 X = 8 check 2(8) - 3 = 13 13 = 13 checks
the series is 2n+3 with n being the previous number 2(5)+3=13 2(13)+3=29 2(29)+3=61 2(61)+3=125 2(125)+3=253<----answer
1+1=2 1+2=3 2+3=5 ... 8+13=21
55x + (-3) = 53x + 7can be written as55x - 3 = 53x + 7subtract 53x from both sides2x - 3 = 7add three to both sides2x = 10divided both sides by 2x = 5
8-9x = 143-44x 44x-9x = 143-8 35x = 135 x = 135/35 = 22/7 or 3.'857142' recurring decimals
3x-1+10 = 53x + 9 = 53x = 5 - 93x = -4x = -4/3
Assuming you mean 3x - 2 = 9x - 5...3x - 2 = 9x - 53x + 3 = 9x3 = 6x0.5 = x
X2 + 44x + 43
8x3 + 12x2 - 44x - 24 = 4(2x3 + 3x2 - 11x - 6) = 4(2x3 - 4x2 + 7x2 - 14x + 3x - 6) = 4[2x2(x - 2) + 7x(x - 2) + 3(x - 2)] = 4(x - 2)(2x2 + 7x + 3) = 4(x - 2)(2x2 + 6x + x + 3) = 4(x - 2)[2x(x + 3) + 1(x + 3)] = 4(x - 2)(x + 3)(2x + 1)
HaHa ofcourse it does who wouldn't get HORN3Y
Prime factors are 2, 2, 3, 3, 3, 13 (Other) Factors are combinations of the above, i.e. 2 x 2 = 4 2 x 3 = 6 2 x 13 = 26 3 x 13 = 39 2 x 2 x 3 = 12 2 x 2 x 13 = 52 2 x 3 x 3 = 18 2 x 3 x 13 = 78 3 x 3 x 13 = 117 2 x 2 x 3 x 3 = 36 2 x 2 x 3 x 13 = 156 2 x 3 x 3 x 13 = 234 3 x 3 x 3 x 13 = 351 2 x 2 x 3 x 3 x 3 = 108 2 x 2 x 3 x 3 x 13 = 468 2 x 3 x 3 x 3 x 13 = 702
the answer is x=8/5 and x=4/3 from: Scott Powell
Factor into primes: 54 = 2*3*3*3 78 = 2*3*13 96 = 2*2*2*2*2*3 What product includes all of the above? You need five 2's, three 3's, and one 13 2*2*2*2*2*3*3*3*13 = 32*27*13 = 11,232
Since 13 is prime and 18=2*3*3, the LCD would be 2*3*3*13, or 234
4.3333