AC=5 AB=8 A=1 B=8 C=5 BC=40
2e-bc/a = 2 2e - bc / a = [2(20) - (3)(10)] / 5 = [40-30]/5 = 10/5
4 BC * * * * * No, it would have been 5 BC because there was no year 0.
Assuming bc stands for b*c and not 10b+c (as in 35 can stand for 3*10+5), the answer is 1/c
10 A.D
460 bc
AC=5 AB=8 A=1 B=8 C=5 BC=40
Sophocles (497/6 bc to 406/5 bc) 497/496 BC ColonusDied406/405 BC
The drive from Surrey, BC, Canada to Penticton, BC, Canada is 243.3 miles. The average driving time is 4 hours 5 minutes when you take BC-5 N, BC-97C E, and TC-1 E.
The probability of ac and bc is 1/5.
BC, which is Before Christ, and BCE, which is Before Common Era, actually refer to the same thing. Years in BC/BCE work in reverse. So 12 BC/BCE came before 5 BC/BCE.
5 bc
2e-bc/a = 2 2e - bc / a = [2(20) - (3)(10)] / 5 = [40-30]/5 = 10/5
It takes about 5 hours.
No, it is the other way around. It goes like this 6,5,4,3,2,1 BC.
5%
3 to 5 buisness days