AC=5
AB=8
A=1
B=8
C=5
BC=40
If those are the legs, the hypotenuse is √113
AB = 2 x 4 (8) C = 3 D = 5
Using the distance formula the length of ab is 5 units
ab = 8-cDivide both sides by ba = (8-c)/b
AB can be found by using the distance formula, which is the square root of (x2-x1)^2 + (y2-y1)^2. In this case, AB= the square root of (-2-(-8))^2 + (-4-(-4))^2 which AB= the square root of 64 + 0 which AB=8.
If these are sides of a triangle then AC can have any value in the interval (3, 13).
ac is 7 if b is 3 and a is 2 a nd c is 5
36
To find the length of side ( AB ) in the right triangle ( ABC ), we can use the Pythagorean theorem, which states that ( AB^2 = AC^2 + BC^2 ). Given ( AC = 7 ) and ( BC = 8 ), we have: [ AB^2 = 7^2 + 8^2 = 49 + 64 = 113 ] Taking the square root, we get: [ AB = \sqrt{113} ] Thus, the length of ( AB ) in simplest radical form is ( \sqrt{113} ).
If it's a right angle triangle then side ac is 10 units in length.
If those are the legs, the hypotenuse is √113
First of all we work out the length of a sides ab, bc, CD, & ad. We know that ab = bc = CD = ad also ae = ac/2 If a to e = 2 then ac = 4 so ab2 + bc2 = ac2 2ab2 = 16 ab2 = 8 ab = 2.8284271247461900976033774484194 so the perimeter = ab * 4 = 11.31
To find the length of segment AB, you simply add the lengths of segments AC and CB together. Since AC is 8 cm and CB is 6 cm, the length of AB is 8 cm + 6 cm = 14 cm. Therefore, segment AB is 14 cm long.
28
Depends which angle is right... If it's angle acb then ab = sqrt(225 + 289) ie 22.67; if it's angle bac then ab = sqrt(289 - 225) ie 8, which seems the more likely.
10
It states that (ab)c = a(bc).