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Q: What is BC if AC is 5 and AB is 8?

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If those are the legs, the hypotenuse is √113

AB = 2 x 4 (8) C = 3 D = 5

Using the distance formula the length of ab is 5 units

ab = 8-cDivide both sides by ba = (8-c)/b

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Related questions

If these are sides of a triangle then AC can have any value in the interval (3, 13).

ac is 7 if b is 3 and a is 2 a nd c is 5

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If it's a right angle triangle then side ac is 10 units in length.

If those are the legs, the hypotenuse is √113

First of all we work out the length of a sides ab, bc, CD, & ad. We know that ab = bc = CD = ad also ae = ac/2 If a to e = 2 then ac = 4 so ab2 + bc2 = ac2 2ab2 = 16 ab2 = 8 ab = 2.8284271247461900976033774484194 so the perimeter = ab * 4 = 11.31

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Depends which angle is right... If it's angle acb then ab = sqrt(225 + 289) ie 22.67; if it's angle bac then ab = sqrt(289 - 225) ie 8, which seems the more likely.

It states that (ab)c = a(bc).

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