If those are the legs, the hypotenuse is √113
AB = 2 x 4 (8) C = 3 D = 5
Using the distance formula the length of ab is 5 units
ab = 8-cDivide both sides by ba = (8-c)/b
AB can be found by using the distance formula, which is the square root of (x2-x1)^2 + (y2-y1)^2. In this case, AB= the square root of (-2-(-8))^2 + (-4-(-4))^2 which AB= the square root of 64 + 0 which AB=8.
If these are sides of a triangle then AC can have any value in the interval (3, 13).
ac is 7 if b is 3 and a is 2 a nd c is 5
36
If it's a right angle triangle then side ac is 10 units in length.
If those are the legs, the hypotenuse is √113
First of all we work out the length of a sides ab, bc, CD, & ad. We know that ab = bc = CD = ad also ae = ac/2 If a to e = 2 then ac = 4 so ab2 + bc2 = ac2 2ab2 = 16 ab2 = 8 ab = 2.8284271247461900976033774484194 so the perimeter = ab * 4 = 11.31
28
Depends which angle is right... If it's angle acb then ab = sqrt(225 + 289) ie 22.67; if it's angle bac then ab = sqrt(289 - 225) ie 8, which seems the more likely.
10
Given that AB = 8 units and AD = 10 units, we can use the ratios of corresponding sides in similar triangles to find the measure of DC. Since triangle ADC is similar to triangle ABC, the ratio of DC to AB is equal to the ratio of AD to AC. Thus, DC/8 = 10/AC. Solving for DC, DC = 8 * 10 / AC.
It states that (ab)c = a(bc).
Note!!!! ignore the S at the end these are the questions 1. side AC= 31 cm, side BC= 20 cm and angle B= 58 degrees 2. side AC= 21 cm, side BC= 28 cm and side AB= 32 cm 3. side AC= 8 cm and side AB= 10 cm please help last 3 questions of my homework. My teacher collects it =(