The answer to this math problem would equal to 20. This is taught in high school math.
5p-7q
If -3q + 4 = 13 then 3q = -9 : q = -3 If 6q = 13 then q = 13/6 = 2 1/6 The question contains an anomaly and is invalid.
7p + 2q = 46 . . . . (A) 5p + 3q = 36 . . . . (B) 3*(A): 21p + 6q = 138 2*(B): 10p + 6q = 72 Subtracting gives 11p = 66 so that p = 6 Substitute for p in (A): 7*6 + 2q = 46 or 42 + 2q = 46 which gives 2q = 4 so that q = 2 Solution: (p, q) = (6,2)
It is not an equation, but q2 meaning q^2 represents q being multiplied by itself.
a/b = 1 so a = b. Then a b = q implies that a = b = q/2 So ab = (q/2)*(q/2) = q2/4
5p-7q
To simplify the expression (7p + 6q - 2p + q), combine like terms. First, combine the (p) terms: (7p - 2p = 5p). Next, combine the (q) terms: (6q + q = 7q). Therefore, the simplified expression is (5p + 7q).
Any positive odd integer can be expressed in the form of ( 2k + 1 ), where ( k ) is a non-negative integer. When dividing this expression by 6, the possible remainders are 1, 3, and 5, corresponding to the cases where ( k ) is congruent to 0, 1, or 2 modulo 3, respectively. Thus, an odd integer can be represented as ( 6q + 1 ), ( 6q + 3 ), or ( 6q + 5 ) for some integer ( q ). This shows that every positive odd integer fits one of these forms.
If -3q + 4 = 13 then 3q = -9 : q = -3 If 6q = 13 then q = 13/6 = 2 1/6 The question contains an anomaly and is invalid.
6q
I'm not exactly sure what you mean by this, but if you'd like to know how to do this in C here: q ^ 2 + 20 q + c
7p + 2q = 46 . . . . (A) 5p + 3q = 36 . . . . (B) 3*(A): 21p + 6q = 138 2*(B): 10p + 6q = 72 Subtracting gives 11p = 66 so that p = 6 Substitute for p in (A): 7*6 + 2q = 46 or 42 + 2q = 46 which gives 2q = 4 so that q = 2 Solution: (p, q) = (6,2)
6
If: 1/2 = q+2/3 Then: q = -1/6
1+2+3+4=10
q3-q2+2q-2 = (q-1)(q2+2) = (q-1)(q+2.5i)(q-2.5i)
It is not an equation, but q2 meaning q^2 represents q being multiplied by itself.