Are you asking to solve for "y" in this? If so, you have to move stuff around. My suggestion: Subtract 2y from both sides, giving you 4y + 30 = 22 Subtraact 30 from both sides, giving you 4y = -8 Divide both sides by 4, giving you y = -2
2x+y=-12-4x-2y=30 x=-y/2+30, you plug this into -12-4x-2y=30 and get -12+2y-120-2y=30 which gives 2y-2y=162. This is not possible, so the equation is unsolvable.
5x+2y = 30 2y = -5x+30 y = -2.5x+15 Therfore the slope is 2.5 and y the intercept is 15.
2y+3y-7y+4=16 -2y=12y=-6Check it-12-18+42+4=16-30+46=1616=16
x+2y = 30 => x= 30-2y x2+y2 =900 (30-2y)2+y2 = 900 (30-2y)(30-2y)+y2 = 900 900-60y-60y+4y2+y2 = 900 5y2-120y = 0 y(5y-120) = 0 y = 0 or y= 24 Substitute the value of y into the original equations to find the value of x: Therefore: x = -18 and y = 24 Check: -18+48 = 30 and (-18)2+242 = 900
Subtract: 3x - 3x - 4y - 2y = 30 - 6 ie -6y = 24 so y = -4 and x = 14/3
4x + 2(3x) = 30 10x = 30 x= 3. Y= 9. (3,9)
3y+5=y-25 2y=-30 y= -15
30 plus 30 equals 60 and 60 minus 38 equals 22
We will see. 3X + 2Y = 15 6X + 4Y = 30 I do not like the look of elimination, so substitution 3X + 2Y = 15 3X = 15 - 2Y X = 5 - 2/3Y -------------- 6(5 - 2/3Y) + 4Y = 30 30 - 12/3Y = 30 30 - 4Y = 30 this is inconsistent in approach 3(5 - 2/3Y) + 2Y = 15 15 - 15/3Y = 15 another bad approach, try elimination to show inconsistency - 2(3X + 2Y = 15) 6X + 4Y + 30 -6X - 4Y = - 30 6X + 4Y = 30 I think it is safe to say these systems of equations are inconsistent --------------------
4x + 2y = 30 Substitute for the variables y could be equal to 3 x could be equal to 6 So that means that, 4 x (6) + 2 x (3)= 30 24 + 2 x (3)= 30 24 + 6= 30 30 = 30
6y + (2-2)y = 6y 6(5) + (2-2)5 = 6(5) 30 + 0 = 30
2x + 30 = 4x + 22 Subtracting 2x from both sides, 30 = 2x + 22 Subtracting 22 from both sides, 8 = 2x Dividing both sides by 2, 4 = x x = 4