X=30 2x+2x+x+30=180; All of the angles in a triangle always add up to 180. Therefore 5x+30=180; subtract 30 to be 5x by itself. Therefore 5x=150; divide by 5 to find x. Therefore X=30 2(30)+2(30)+30+30=180
x: x = 15 y: y = 10 z: z = -5
First we have to find the width. Let the width be x: 2(12+x) = 30 24+2x = 30 2x = 30-24 2x = 6 x = 3 So the width is 3 units Area = length*width = 12*3 = 36 square units
First you square root everything on both sides to cancel the squares. 30+B=78 Then subtract 30 from both sides to get B=48. So the answer is B=48
-5x + 6y = 30At the x-intercept, y=0:-5x = 30 ==> x = -6At the y-intercept, x=0:6y = 30 ==> y = 5
(3,3)
30+12x = 6(5+2x)
2x + 30 = 4x + 10 Subtracting 2x from each side, 30 = 2x + 10 Subtracting 10 from both sides 20 = 2x Dividing both sides by 2 10 = x x = 10
-1
2x + 6 - 6x = 30= 6 - 4x = 30= -4x = 24= 4x = -24= x = -6
30 plus 30 equals 60 and 60 minus 38 equals 22
Subtract 2x from each side: 30 = 10x - 50;Add 50 to each side: 80 = 10xDivide each side by 10: 8 = x
It can be simplified to: 2x+33
I am having difficulty understanding your question. 12 + 20 = 10 is obviously false (12 + 20 = 32).If 4x + 14 = 2x + 30, then x must equal 8.
Set up the equation and solve: 8x + 8 = 2x +38 (subtract 2x and 8 from both sides of the equation) 6x = 30 (divide both sides of the equation by 6) x = 5
12
12x - 5(2x - 6) = 30 12 x - 10x + 30 = 30 2x = 0, x = 0 y = -6