784
1029
1 x 7 = 7 7 x 1 = 7
short answer -1 and -7 long worked answer let x = one of the integers let y = the other integer x+y = -8 xy = 7 solve for y y = -8 - x plug y in x(-8 - x) = 7 rearrange -x^2 - 8x - 7 = 0 divide both sides by -1 x^2 + 8x + 7 = 0 factor (x + 7)(x + 1) = 0 x = -1, -7 y = -8 - x so y = -8 + 1 = -7 or -8 + 7 = -1 so when x = -1, y = -7 when x = -7, y = -1
x = 7 7-4/3 x 7 = 1/7 3/21 = 1/7
x : 7 or 1 : 7/x or x/7 : 1
784
2744 = 1 x 1 x 2 x 2 x 2 x 7 x 7 x 7 Make 3 groups of these factors and multiply the numbers in each group to get 3 numbers, eg: {1}, {1}, {2, 2, 2, 7, 7, 7} = 1 x 1 x 2744 {1}, {1, 2}, {2, 2, 7, 7, 7} = 1 x 2 x 1372 {1, 2}, {1, 2, 7}, {2, 7, 7} = 2 x 14 x 98 {1, 2, 7}, {1, 2, 7}, {2, 7} = 14 x 14 x 14 There are many more such answers.
1029
7a3 = 7 x a x a x a.
Yes, -7 = -1 x 7 (or 1 x -7)
1 x 7, 7 x 1
49 x 1/7 = 7
1 x 7 = 7 7 x 1 = 7
(x - 7)(x - 1) or (x + 7)(x + 1) depending on sign of 8x so zero is +/- 7 and +/- 1
1, 7, 49: 1 x 49, 7 x 7, 49 x 1
1 x 7, 7 x 1